Math Problem Statement

Is the relationship linear, exponential, or neither?

Solution

The question asks whether the relationship between xx and yy is linear, exponential, or neither based on the data points:

x & y \\ \hline 9 & 13 \\ 14 & 16 \\ 19 & 19 \\ 24 & 22 \\ \end{array}$$ ### Step 1: Check for a Linear Relationship For a relationship to be linear, the rate of change (or slope) between consecutive points should be constant. We can calculate the differences in $$y$$-values divided by the differences in $$x$$-values (i.e., $$\Delta y / \Delta x$$) for each consecutive pair of points: 1. Between $$(9, 13)$$ and $$(14, 16)$$: $$\frac{16 - 13}{14 - 9} = \frac{3}{5} = 0.6$$ 2. Between $$(14, 16)$$ and $$(19, 19)$$: $$\frac{19 - 16}{19 - 14} = \frac{3}{5} = 0.6$$ 3. Between $$(19, 19)$$ and $$(24, 22)$$: $$\frac{22 - 19}{24 - 19} = \frac{3}{5} = 0.6$$ Since the rate of change is consistent (0.6) across each interval, this relationship is **linear**. ### Answer The correct answer is: - **A) Linear** Would you like further details on how to identify linear, exponential, or other relationships? --- ### Related Questions 1. How do you calculate the rate of change between two points? 2. What are the key differences between linear and exponential relationships? 3. Can a function be both linear and exponential? Why or why not? 4. How can you determine if a relationship is "neither" linear nor exponential? 5. How do real-world examples illustrate linear relationships? **Tip:** For linear relationships, always check if the differences in $$y$$-values divided by $$x$$-values remain constant!

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Math Problem Analysis

Mathematical Concepts

Algebra
Linear Relationships
Exponential Relationships

Formulas

Rate of change formula: (y2 - y1) / (x2 - x1)

Theorems

Slope formula for linear relationships

Suitable Grade Level

Grades 8-10