Math Problem Statement

In the xy-plane, the graph of a rational function g(x) has a vertical asymptote at x = -5. Which of the following expressions could represent g(x)?

Solution

To solve this problem, we need to determine which function g(x)g(x) has a vertical asymptote at x=5x = -5. A vertical asymptote in a rational function P(x)Q(x)\frac{P(x)}{Q(x)} occurs where the denominator Q(x)=0Q(x) = 0, but the numerator P(x)0P(x) \neq 0 at that point.

Step-by-Step Solution

  1. Factor the Denominator of Each Option: We will focus on the factorization of the denominator in each function. We’re looking for denominators that have a factor of x+5x + 5, since setting x+5=0x + 5 = 0 results in x=5x = -5, creating a potential asymptote.

  2. Evaluate Each Option:

    • Option A: g(x)=x2+9x+20x2x12g(x) = \frac{x^2 + 9x + 20}{x^2 - x - 12}

      • Denominator: x2x12x^2 - x - 12.
      • Factoring: x2x12=(x+3)(x4)x^2 - x - 12 = (x + 3)(x - 4).
      • This does not produce x+5=0x + 5 = 0, so there is no asymptote at x=5x = -5.
    • Option B: g(x)=x2+7x+12x2x20g(x) = \frac{x^2 + 7x + 12}{x^2 - x - 20}

      • Denominator: x2x20x^2 - x - 20.
      • Factoring: x2x20=(x+5)(x4)x^2 - x - 20 = (x + 5)(x - 4).
      • This produces a factor x+5x + 5, which implies a vertical asymptote at x=5x = -5.
      • This option could be correct.
    • Option C: g(x)=x22x15x2+x20g(x) = \frac{x^2 - 2x - 15}{x^2 + x - 20}

      • Denominator: x2+x20x^2 + x - 20.
      • Factoring: x2+x20=(x+5)(x4)x^2 + x - 20 = (x + 5)(x - 4).
      • This produces a factor x+5x + 5, implying a vertical asymptote at x=5x = -5.
      • This option could also be correct.
    • Option D: g(x)=x2+8x+15x27x+12g(x) = \frac{x^2 + 8x + 15}{x^2 - 7x + 12}

      • Denominator: x27x+12x^2 - 7x + 12.
      • Factoring: x27x+12=(x3)(x4)x^2 - 7x + 12 = (x - 3)(x - 4).
      • This does not produce x+5=0x + 5 = 0, so there is no asymptote at x=5x = -5.
  3. Conclusion:

    • The correct answers are Option B and Option C, as both have denominators with a factor of x+5x + 5, which would produce a vertical asymptote at x=5x = -5.

Would you like further details on the factorization process or have any questions?


Related Questions to Explore

  1. How do you determine if a rational function has a hole instead of an asymptote?
  2. Why does a factor in the denominator cause a vertical asymptote in rational functions?
  3. What are the differences between vertical asymptotes and horizontal asymptotes?
  4. How do you determine the horizontal asymptote of a rational function?
  5. What conditions create holes in the graph of a rational function?

Tip

When factoring quadratic expressions, always check for common binomial factors in both the numerator and the denominator to identify potential vertical asymptotes or holes.

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Math Problem Analysis

Mathematical Concepts

Rational Functions
Vertical Asymptotes
Factoring Polynomials

Formulas

Vertical Asymptote Condition: Set denominator to 0 and ensure numerator is non-zero

Theorems

Vertical asymptotes occur where the denominator of a rational function is zero and the numerator is not zero

Suitable Grade Level

High School (Grades 9-12)