Math Problem Statement

Identify a and b for the hyperbola with equation \(\frac{x^2}{a^2} - \frac{y^2}{b^2} = 1\).

Solution

To solve this problem, let’s analyze the hyperbola and its equation:

The general equation for a hyperbola in the form shown is:

x2a2y2b2=1\frac{x^2}{a^2} - \frac{y^2}{b^2} = 1

Here:

  • aa represents the distance from the center of the hyperbola to the vertices along the x-axis.
  • bb is used to determine the asymptotes, which are given by the equations: y=±baxy = \pm \frac{b}{a}x

Steps:

  1. Identify aa:

    • The vertices are located at the x-intercepts of the hyperbola.
    • Observing the graph, the vertices are at x=±5x = \pm 5.
    • Therefore, a=5a = 5.
  2. Identify bb:

    • The asymptotes are given as dashed lines, and their slopes can be calculated as ±ba\pm \frac{b}{a}.
    • From the graph, the slope of the asymptotes is ±2\pm 2, so: ba=2b=2a=25=10\frac{b}{a} = 2 \quad \Rightarrow \quad b = 2a = 2 \cdot 5 = 10

Solution:

a=5,b=10a = 5, \quad b = 10

Let me know if you'd like further explanation or have any other questions! Here are 5 related questions to explore:

  1. How do you derive the equation of the asymptotes of a hyperbola?
  2. What is the difference between hyperbolas with horizontal vs. vertical orientations?
  3. Can you identify the foci of this hyperbola? (Hint: Use c2=a2+b2c^2 = a^2 + b^2.)
  4. How do the equations change for a hyperbola centered at (h,k)(h, k)?
  5. What are the real-world applications of hyperbolas in physics or engineering?

Tip: Always double-check the slopes of the asymptotes to confirm the relationship between aa and bb.

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Math Problem Analysis

Mathematical Concepts

Hyperbolas
Asymptotes
Vertices

Formulas

General equation of a hyperbola: \(\frac{x^2}{a^2} - \frac{y^2}{b^2} = 1\)
Asymptote slopes: \(\pm \frac{b}{a}\)
Distance to vertices: \(a\)

Theorems

Properties of hyperbolas
Relationship between asymptotes and hyperbola axes

Suitable Grade Level

Grades 10-12