Math Problem Statement

Test the hypothesis using the P-value approach. H₀: p = 0.79 versus H₁: p ≠ 0.79. n = 500, x = 380, α = 0.01. Is np₀(1 - p₀) ≥ 10?

Solution

The image contains a hypothesis test question using the P-value approach. Here's a breakdown of the problem:

  • Hypotheses:

    • H0H_0: p=0.79p = 0.79
    • H1H_1: p0.79p \neq 0.79
  • Given data:

    • Sample size: n=500n = 500
    • Successes: x=380x = 380
    • Significance level: α=0.01\alpha = 0.01
  • Requirement check: The question asks to verify if the condition np0(1p0)10np_0(1 - p_0) \geq 10 is satisfied, where p0=0.79p_0 = 0.79.

Calculation:

  1. n=500n = 500
  2. p0=0.79p_0 = 0.79
  3. 1p0=10.79=0.211 - p_0 = 1 - 0.79 = 0.21

Now calculate: np0(1p0)=500×0.79×0.21=500×0.1659=82.95np_0(1 - p_0) = 500 \times 0.79 \times 0.21 = 500 \times 0.1659 = 82.95

Since 82.951082.95 \geq 10, the condition is met.

Conclusion:

  • The correct answer is Option A: "Yes, because np0(1p0)=82.95np_0(1 - p_0) = 82.95."

Would you like further details or explanations?

Here are five related questions:

  1. What is the next step after verifying the condition np0(1p0)10np_0(1 - p_0) \geq 10 in a hypothesis test?
  2. How do you calculate the test statistic for this hypothesis test?
  3. What is the role of the significance level α=0.01\alpha = 0.01 in hypothesis testing?
  4. How do you interpret the P-value in hypothesis testing?
  5. What is the difference between a one-tailed and a two-tailed hypothesis test?

Tip: Always ensure that the condition np0(1p0)10np_0(1 - p_0) \geq 10 is checked before proceeding with normal approximation in hypothesis testing.

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Math Problem Analysis

Mathematical Concepts

Hypothesis Testing
P-value Approach
Binomial Proportion

Formulas

np₀(1 - p₀) ≥ 10
P-value formula for hypothesis testing

Theorems

Central Limit Theorem (for approximating binomial distribution)
Normal Approximation to the Binomial

Suitable Grade Level

College Level - Statistics