(CO 5) An executive claims that her employees spend less than 2.5 hours each week in meetings. Write the null and alternative hypotheses.

Group of answer choices

Ho: μ < 2.5, Ha: μ = 2.5

Ho: μ = 2.5, Ha: μ > 2.5

Ho: μ = 2.5, Ha: μ < 2.5

Ho: μ = 2.5, Ha: μ ≥ 2.5

Given that the executive claims her employees spend less than 2.5 hours each week in meetings, the hypotheses can be structured as follows:

- The **null hypothesis (Ho)** is a statement of no effect or the status quo, which would assume that employees spend exactly 2.5 hours in meetings.
- The **alternative hypothesis (Ha)** is what the executive is trying to prove, which is that employees spend less than 2.5 hours in meetings.

Thus, the correct pair of hypotheses is:

**Ho: μ = 2.5, Ha: μ < 2.5**

This corresponds to the third option:

- **Ho: μ = 2.5, Ha: μ < 2.5**

Would you like more details or have any questions?

Here are 5 related questions to consider:
1. What are the steps to conduct a hypothesis test for this claim?
2. What type of statistical test would be appropriate for these hypotheses?
3. How does one determine the critical value for a one-tailed test?
4. What does it mean if the null hypothesis is rejected?
5. How could you estimate the population mean time employees spend in meetings from a sample?

**Tip:** When framing hypotheses, always ensure that the null hypothesis represents the statement being tested, while the alternative hypothesis represents the claim or effect you wish to investigate.

Understand hypothesis testing with an example of null and alternative hypotheses. Learn how to structure hypotheses for claims about meeting times in business settings. Suitable for advanced learners and professionals.

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