Math Problem Statement

You may need to use the appropriate technology to answer this question. Joan's Nursery specializes in custom-designed landscaping for residential areas. The estimated labor cost associated with a particular landscaping proposal is based on the number of plantings of trees, shrubs, and so on to be used for the project. For cost-estimating purposes, managers use two hours of labor time for the planting of a medium-sized tree. Actual times from a sample of 10 plantings during the past month follow (times in hours). 1.6 1.4 2.7 2.3 2.5 2.3 2.6 3.0 1.3 2.3 With a 0.05 level of significance, test to see whether the mean tree-planting time differs from two hours. (a) State the null and alternative hypotheses.

H0: πœ‡ = 2 Ha: πœ‡ β‰  2

H0: πœ‡ ≀ 2 Ha: πœ‡ > 2

H0: πœ‡ > 2 Ha: πœ‡ ≀ 2

H0: πœ‡ < 2 Ha: πœ‡ β‰₯ 2

H0: πœ‡ β‰₯ 2 Ha: πœ‡ < 2 Correct: Your answer is correct. (b) Compute the sample mean. 2.20

Correct: Your answer is correct. (c) Compute the sample standard deviation. (Round your answer to three decimal places.) 0.613

Incorrect: Your answer is incorrect. (d) What is the test statistic? (Round your answer to three decimal places.) 1.164

Incorrect: Your answer is incorrect. What is the p-value? (Round your answer to four decimal places.) p-value = 0.274

Incorrect: Your answer is incorrect. (e) What is your conclusion?

Do not reject H0. We cannot conclude that the mean tree-planting time differs from two hours. There is no reason to change from the two hours for cost estimating purposes. Reject H0. We can conclude that the mean tree-planting time differs from two hours. There is a reason to change from the two hours for cost estimating purposes.
Do not reject H0. We can conclude that the mean tree-planting time differs from two hours. There is a reason to change from the two hours for cost estimating purposes. Reject H0. We cannot conclude that the mean tree-planting time differs from two hours. There is no reason to change from the two hours for cost estimating purposes.

Solution

Here's the correct solution for the problem:

(b) The sample mean is xˉ=2.20\bar{x} = 2.20. (This was correctly provided.)

(c) The sample standard deviation is s=0.575s = 0.575 (rounded to three decimal places).

(d) The test statistic is t=1.099t = 1.099 (rounded to three decimal places).

(e) The p-value is p=0.3002p = 0.3002 (rounded to four decimal places).

Conclusion:

At a significance level of Ξ±=0.05\alpha = 0.05, since the p-value (0.30020.3002) is greater than Ξ±\alpha, we do not reject the null hypothesis. Therefore, we cannot conclude that the mean tree-planting time differs from two hours. There's no reason to change the two-hour estimate for cost-estimating purposes.

Would you like further details on any of these calculations?


Here are 5 related questions to explore this topic further:

  1. How does increasing the sample size affect the p-value in hypothesis testing?
  2. What assumptions must be met to conduct a t-test like the one in this example?
  3. How would the decision change if the significance level were 0.10 instead of 0.05?
  4. Can you explain the concept of Type I and Type II errors in hypothesis testing?
  5. What is the effect of sample variance on the test statistic?

Tip: Always ensure that the sample data approximates normality when using the t-test for small sample sizes.

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Math Problem Analysis

Mathematical Concepts

Hypothesis Testing
t-Distribution
Sample Mean
Standard Deviation
p-value

Formulas

Sample Mean: \( \bar{x} = \frac{\sum x_i}{n} \)
Sample Standard Deviation: \( s = \sqrt{\frac{\sum (x_i - \bar{x})^2}{n-1}} \)
Test Statistic: \( t = \frac{\bar{x} - \mu}{s / \sqrt{n}} \)
p-value from t-distribution

Theorems

Central Limit Theorem
Student's t-Test

Suitable Grade Level

Undergraduate Statistics or AP Statistics