Math Problem Statement

g(x)=3x-3, f(x)=x2+1. find (g+f)(n)

Solution

To find (g+f)(n)(g + f)(n), we need to add the functions g(x)g(x) and f(x)f(x) and then substitute x=nx = n.

Step 1: Add the functions g(x)g(x) and f(x)f(x)

Given:

  • g(x)=3x3g(x) = 3x - 3
  • f(x)=x2+1f(x) = x^2 + 1

Now, add g(x)g(x) and f(x)f(x): (g+f)(x)=g(x)+f(x)(g + f)(x) = g(x) + f(x) (g+f)(x)=(3x3)+(x2+1)(g + f)(x) = (3x - 3) + (x^2 + 1) Simplifying: (g+f)(x)=x2+3x3+1(g + f)(x) = x^2 + 3x - 3 + 1 (g+f)(x)=x2+3x2(g + f)(x) = x^2 + 3x - 2

Step 2: Substitute x=nx = n

Now, substitute nn into (g+f)(x)(g + f)(x): (g+f)(n)=n2+3n2(g + f)(n) = n^2 + 3n - 2

So, (g+f)(n)=n2+3n2(g + f)(n) = n^2 + 3n - 2.

Would you like a detailed explanation on how I simplified the expression?

Here are 5 questions related to this problem:

  1. How do you find the sum of two functions in general?
  2. What is the process of simplifying polynomials?
  3. How do you find the value of a function at a specific point?
  4. Can we subtract, multiply, or divide functions similarly?
  5. What is function composition and how is it different from function addition?

Tip: When adding functions, always combine like terms carefully to simplify the resulting expression.

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Math Problem Analysis

Mathematical Concepts

Algebra
Function Addition
Polynomials

Formulas

(g + f)(x) = g(x) + f(x)
(g + f)(n) = n^2 + 3n - 2

Theorems

Basic Function Addition Theorem

Suitable Grade Level

Grades 8-10