To determine how many whole boxes that measure $2 \, \text{ft} \times 2 \, \text{ft} \times 2 \, \text{ft}$ can fit into a room measuring $9 \, \text{ft} \times 9 \, \text{ft} \times 9 \, \text{ft}$, we need to calculate the volume of the room and the volume of each box, then see how many boxes can fit.

Step 1: Calculate the volume of the room

The volume of the room is:

$V_{\text{room}} = 9 \, \text{ft} \times 9 \, \text{ft} \times 9 \, \text{ft} = 729 \, \text{cubic feet}$

Step 2: Calculate the volume of each box

The volume of each box is:

$V_{\text{box}} = 2 \, \text{ft} \times 2 \, \text{ft} \times 2 \, \text{ft} = 8 \, \text{cubic feet}$

Step 3: Determine how many boxes fit in the room

We divide the volume of the room by the volume of one box to see how many boxes can fit:

$\frac{V_{\text{room}}}{V_{\text{box}}} = \frac{729 \, \text{cubic feet}}{8 \, \text{cubic feet}} = 91.125$

However, since we can only fit whole boxes, we round down to the nearest whole number. Therefore, the total number of whole boxes that can fit is:

$\text{Total boxes} = 91$

Thus, none of the options given exactly match the calculation, but based on the math, the closest correct answer to the total number of whole boxes is 91.

Would you like more clarification on how we calculated this?

Here are 5 related questions:

1. What if the room were 10ft x 10ft x 10ft—how many boxes could fit then?
2. How would the number of boxes change if the boxes were 3ft x 3ft x 3ft?
3. Can boxes of irregular shapes affect the number of boxes that can fit?
4. How do you calculate the volume of an irregularly shaped container?
5. What if the room had slanted walls—how would you account for the lost space?

Tip: Always round down when determining how many whole objects (like boxes) fit into a space.