Math Problem Statement
During one shift, the express lane clerk recorded how many times customers violated the "10 items or less" rule for his lane. In particular, he recorded how many items over the limit each violator placed on the conveyor belt. This data is summarized in the histogram below. NOTE: The last class actually represents "7 or more items," not just 7 items.
2 4 6 8 10 12 14 0.5 1.5 2.5 3.5 4.5 5.5 6.5 7.5
items over 10
Frequency [Graphs generated by this script: setBorder(54,40,20,5); initPicture(0,7.5,0,14);axes(1000,2,1,1000,2); fill="blue"; stroke="black";line([0.5,-0.28],[0.5,0.28]); text([0.5,0],"0.5","below");line([1.5,-0.28],[1.5,0.28]); text([1.5,0],"1.5","below");line([2.5,-0.28],[2.5,0.28]); text([2.5,0],"2.5","below");line([3.5,-0.28],[3.5,0.28]); text([3.5,0],"3.5","below");line([4.5,-0.28],[4.5,0.28]); text([4.5,0],"4.5","below");line([5.5,-0.28],[5.5,0.28]); text([5.5,0],"5.5","below");line([6.5,-0.28],[6.5,0.28]); text([6.5,0],"6.5","below");line([7.5,-0.28],[7.5,0.28]); text([7.5,0],"7.5","below");textabs([165,0],"# items over 10","above");textabs([0,115],"Frequency","right",90);rect([0.5,0],[1.5,6]);rect([1.5,0],[2.5,9]);rect([2.5,0],[3.5,11]);rect([3.5,0],[4.5,14]);rect([4.5,0],[5.5,12]);rect([5.5,0],[6.5,8]);rect([6.5,0],[7.5,5]);]
What is the frequency of times the limit was exceeded by less than 4 items?
Solution
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Math Problem Analysis
Mathematical Concepts
Histogram interpretation
Frequency distribution
Summation
Formulas
Sum of frequencies for specific intervals
Theorems
Basic histogram interpretation principles
Suitable Grade Level
Grades 6-8
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