Math Problem Statement

During one shift, the express lane clerk recorded how many times customers violated the "10 items or less" rule for his lane. In particular, he recorded how many items over the limit each violator placed on the conveyor belt. This data is summarized in the histogram below. NOTE: The last class actually represents "7 or more items," not just 7 items.

2 4 6 8 10 12 14 0.5 1.5 2.5 3.5 4.5 5.5 6.5 7.5

items over 10

Frequency [Graphs generated by this script: setBorder(54,40,20,5); initPicture(0,7.5,0,14);axes(1000,2,1,1000,2); fill="blue"; stroke="black";line([0.5,-0.28],[0.5,0.28]); text([0.5,0],"0.5","below");line([1.5,-0.28],[1.5,0.28]); text([1.5,0],"1.5","below");line([2.5,-0.28],[2.5,0.28]); text([2.5,0],"2.5","below");line([3.5,-0.28],[3.5,0.28]); text([3.5,0],"3.5","below");line([4.5,-0.28],[4.5,0.28]); text([4.5,0],"4.5","below");line([5.5,-0.28],[5.5,0.28]); text([5.5,0],"5.5","below");line([6.5,-0.28],[6.5,0.28]); text([6.5,0],"6.5","below");line([7.5,-0.28],[7.5,0.28]); text([7.5,0],"7.5","below");textabs([165,0],"# items over 10","above");textabs([0,115],"Frequency","right",90);rect([0.5,0],[1.5,6]);rect([1.5,0],[2.5,9]);rect([2.5,0],[3.5,11]);rect([3.5,0],[4.5,14]);rect([4.5,0],[5.5,12]);rect([5.5,0],[6.5,8]);rect([6.5,0],[7.5,5]);]

What is the frequency of times the limit was exceeded by less than 4 items?

Solution

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Math Problem Analysis

Mathematical Concepts

Histogram interpretation
Frequency distribution
Summation

Formulas

Sum of frequencies for specific intervals

Theorems

Basic histogram interpretation principles

Suitable Grade Level

Grades 6-8