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The problem asks how many fish were between 30 cm and 40 cm long, using the histogram provided.

To solve this:
1. The histogram shows frequency density on the y-axis and fish length (cm) on the x-axis.
2. For the interval 30 cm to 40 cm, observe the height of the bar and its width (which is the range of the fish lengths).
3. The total number of fish in this range is given by multiplying the frequency density (height) by the width of the bar (length range).

### Steps:
- From the histogram, the height (frequency density) for the 30–40 cm range is **1.5**.
- The width of the bar is the difference in length: \( 40 \, \text{cm} - 30 \, \text{cm} = 10 \, \text{cm} \).

Thus, the number of fish in this range is:
\[
\text{Number of fish} = \text{Frequency density} \times \text{Width} = 1.5 \times 10 = 15
\]

So, **15 fish** were between 30 cm and 40 cm long.

Would you like more details or have any questions about this problem?

Here are 5 related questions to explore:
1. How would you calculate the number of fish for a different range?
2. What is the importance of frequency density in histograms?
3. How does the width of bars affect the interpretation of histograms?
4. Can you determine the total number of fish from the entire histogram?
5. How does this histogram differ from a bar chart?

**Tip:** In histograms, always multiply the frequency density by the class width to get the actual frequency.

How many of the fish were between 30 cm and 40 cm long?

Learn how to calculate the number of fish that were between 30 cm and 40 cm long based on the frequency density shown in a histogram. This problem covers key concepts like frequency density, multiplication, and reading histograms. Suitable for students in Grades 8-10.

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