A hiker walks from the drop-off and initially covers 3000 m, 35° north of west. He then traveled another 5500 m heading to 10° north of west. Finally, he reached his destination by walking 1500 m due north. What is his total displacement?ILLUSTRATE THIS

The hiker's total displacement is approximately **8912.66 meters** at an angle of **27.94° north of west**. This displacement is represented by the purple vector in the diagram.

Would you like any further details or clarifications?

Here are some additional questions to consider:
1. How would the displacement change if the final leg were longer?
2. What would the total displacement be if one of the angles was different?
3. Can you calculate the average speed of the hiker if the total time was given?
4. How would the direction of the resultant vector change if one leg had a different bearing?
5. Can you calculate the time taken for each leg of the journey if the hiker's speed was constant?

**Tip:** Always use vector components to solve problems involving multiple directions of motion.

A hiker walks from the drop-off and initially covers 3000 m, 35° north of west. He then traveled another 5500 m heading to 10° north of west. Finally, he reached his destination by walking 1500 m due north. What is his total displacement? ILLUSTRATE THIS

Solve the problem of calculating the hiker's total displacement using vector addition and trigonometry. The hiker travels 3000 m at 35° north of west, 5500 m at 10° north of west, and 1500 m due north. This step-by-step solution provides a clear breakdown of vector components and displacement calculations, suitable for Grades 10-12.

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