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Let's analyze the question and data provided in the image.

The table in the question shows the number of students (in thousands) who graduated from high school each year from 1996 to 2005. Here's a breakdown of the problem requirements:

### Problem Details

1. **Data Points (Year and Graduates)**:
   - The table provides values of \( x \) (year) and \( y \) (number of graduates in thousands).
   - \( x = \) the year - 1996, so 1996 corresponds to \( x = 0 \), 1997 to \( x = 1 \), and so on up to 2005 (corresponding to \( x = 9 \)).

2. **Question Parts**:
   - **(a)** Plot a scatter diagram using the points \( P_1(1, 2633) \) and \( P_2(8, 2935) \). Then find the equation of the linear function passing through these points.
   - **(b)** Use the model obtained in part (a) to estimate the number of high school graduates in 2010.

### Solution Steps

#### Part (a): Linear Equation

1. **Identify the Points**:
   - \( P_1(1, 2633) \): Corresponds to \( x = 1 \), \( y = 2633 \).
   - \( P_2(8, 2935) \): Corresponds to \( x = 8 \), \( y = 2935 \).

2. **Calculate the Slope \( m \)**:
   \[
   m = \frac{y_2 - y_1}{x_2 - x_1} = \frac{2935 - 2633}{8 - 1} = \frac{302}{7} \approx 43.14
   \]

3. **Form the Linear Equation**:
   Using the point-slope form \( y - y_1 = m(x - x_1) \):
   \[
   y - 2633 = 43.14(x - 1)
   \]
   Expanding and simplifying gives:
   \[
   y = 43.14x + 2589.86
   \]
   So, the equation of the linear function is approximately:
   \[
   y = 43.14x + 2589.86
   \]

#### Part (b): Estimate for 2010

1. **Convert Year 2010 to \( x \)**:
   - 2010 is 14 years after 1996, so \( x = 14 \).

2. **Substitute \( x = 14 \) into the Equation**:
   \[
   y = 43.14(14) + 2589.86
   \]
   Calculating this:
   \[
   y \approx 43.14 \cdot 14 + 2589.86 = 603.96 + 2589.86 \approx 3193.82
   \]
   So, the estimated number of graduates in 2010 is approximately **3194 thousand**.

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Would you like further details on any specific part of the solution? 

### Additional Questions to Consider

1. How would the results differ if a different pair of points were chosen?
2. What would happen if a quadratic model was used instead of a linear one?
3. How does the accuracy of this linear model change for years further away from the provided data range?
4. What assumptions are we making by using a linear model for this data?
5. Could this model be used to estimate graduates for years before 1996?

**Tip**: For linear models, always verify if a linear trend reasonably fits the data, especially when projecting far from the original range.

The table below shows the numbers of students, in thousands, who have graduated from high school for the years 1996 to 2005. a) Using x = 0 to correspond to 1996, draw a scatter diagram of the data and write the equation of a linear function that fits the data on P1(1, 2633) and P2(8, 2935). b) Use the model to estimate the expected number of high school graduates in 2010.

Analyze the data on high school graduates from 1996 to 2005 and learn to create a linear model. This problem includes plotting a scatter diagram and finding a linear equation based on two points, then using the model to predict graduates for the year 2010. Suitable for high school students in Grades 9-12.

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