Math Problem Statement

solve them. i want to see the complete solutions to them

Solve the exercises provided in the uploaded image. I want to see the complete solutions to them.

Solution

I will solve the problems one by one in detail. Let's begin with the first exercise.

1. Problem:

Let HGH \leq G (subgroup). Show that K=gGgHg1K = \bigcap_{g \in G} gHg^{-1} is a normal subgroup of GG.


Solution:

  1. KK is defined as the intersection of all conjugates of HH in GG: K=gGgHg1.K = \bigcap_{g \in G} gHg^{-1}. This means KgHg1K \subseteq gHg^{-1} for all gGg \in G.

  2. Closure of KK:
    Since KK is a subgroup of GG, it is closed under group operations (multiplication and taking inverses).

  3. Normality of KK:
    To prove KGK \trianglelefteq G, we need to show that gKg1=KgKg^{-1} = K for all gGg \in G.

    • Take xKx \in K. Then xgHg1x \in g'Hg'^{-1} for all gGg' \in G.
      Conjugating xx by gg, we have: gxg1g(gHg1)g1.gxg^{-1} \in g(g'Hg'^{-1})g^{-1}. Using associativity of group operations: g(gHg1)g1=(gg)H(gg)1.g(g'Hg'^{-1})g^{-1} = (gg')H(gg')^{-1}. Hence, gxg1gGgHg1=Kgxg^{-1} \in \bigcap_{g' \in G} g'Hg'^{-1} = K.
      This proves gKg1KgKg^{-1} \subseteq K. Similarly, KgKg1K \subseteq gKg^{-1}, so gKg1=KgKg^{-1} = K.

Thus, KK is a normal subgroup of GG.


2. Problem:

Let HGH \leq G. If g2Hg^2 \in H and gHg1=HgHg^{-1} = H, then show G/HG/H is abelian.


Solution:

  1. G/HG/H is the set of cosets of HH in GG, and we want to show that the operation on these cosets is commutative.

  2. Let g,hGg, h \in G, and consider the cosets gHgH and hHhH.
    Their product in G/HG/H is: (gH)(hH)=ghH.(gH)(hH) = ghH.

  3. To prove commutativity, we need to show: ghH=hgH.ghH = hgH.

  4. Given that gHg1=HgHg^{-1} = H, it follows that gH=HggH = Hg, and similarly hH=HhhH = Hh.

  5. Also, since g2Hg^2 \in H, we have gg=g2Hg \cdot g = g^2 \in H, so gg behaves like an element of HH under coset multiplication.

  6. Since all elements commute within HH, and gHg1=HgHg^{-1} = H, this implies gh=hggh = hg mod HH.

Thus, G/HG/H is abelian.


Would you like to proceed with the next problems or have questions about these?

Follow-up Questions:

  1. What does gHg1gHg^{-1} represent in a group structure?
  2. Can we generalize the result of Problem 1 to infinite groups?
  3. How does G/HG/H being abelian affect the group GG?
  4. What is the significance of normal subgroups in group theory?
  5. Are there examples of G/HG/H not being abelian when conditions differ?

Tip: Normal subgroups are critical when studying the quotient structure of groups—ensure you understand their properties fully!

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Math Problem Analysis

Mathematical Concepts

Group Theory
Normal Subgroups
Quotient Groups
Cyclic Groups
Homomorphisms

Formulas

K = ⋂ gHg⁻¹ (Intersection of conjugates)
Coset multiplication: (gH)(hH) = ghH
|G| = |H||G/H| (Lagrange's Theorem)

Theorems

Normal Subgroup Theorem
Isomorphism Theorems
Fundamental Theorem of Cyclic Groups

Suitable Grade Level

Undergraduate