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To solve this problem, let’s break it down step-by-step.

1. **Identify Costs**:
   - The first copy costs 18 cents.
   - Each additional copy costs 12 cents.

2. **Set Up Equation**:
   - Let $ x $ be the total number of copies.
   - We know that the cost of the first copy is 18 cents, and the remaining $ x - 1 $ copies cost 12 cents each.
   - The total cost is given as $3.00, which is equivalent to 300 cents.

   So, the equation for the total cost becomes:
   \[
   18 + 12(x - 1) = 300
   \]

3. **Solve for $ x $**:
   \[
   18 + 12(x - 1) = 300
   \]
   \[
   18 + 12x - 12 = 300
   \]
   \[
   6 + 12x = 300
   \]
   \[
   12x = 294
   \]
   \[
   x = \frac{294}{12}
   \]
   \[
   x = 24.5
   \]

Since $ x $ represents the number of copies, it must be a whole number. Thus, we round down to the nearest whole number, which is 24.

4. **Conclusion**:
   - The greatest number of copies you can get for $3.00 is **24**.

### Answer:
The correct choice is **(D) 24**.

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Would you like a further breakdown or have any questions?

Here are some additional questions to explore:

1. How would the answer change if the cost per additional copy was 15 cents instead?
2. What if the budget was $4.00 instead of $3.00?
3. How would you set up a general formula for any initial cost and per-copy cost?
4. Can you calculate the total cost if you purchase 30 copies instead?
5. What would be the answer if the cost for each copy was the same, at 12 cents each?

**Tip:** When dealing with piecewise or sequential cost structures, separate the fixed and variable parts clearly for easier calculations.

Copy Cat Copies charges 18 cents for the first copy and 12 cents for each additional copy. What is the greatest number of copies you can get for $3.00?

Find out how many copies you can purchase with a budget of $3 at Copy Cat Copies, given the cost structure of 18 cents for the first copy and 12 cents for each additional copy. This algebra problem involves setting up and solving a linear equation, suitable for students in Grades 6-8.

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