Math Problem Statement

Given the following positions below, find the Great Circle Distance, initial course and final course: Departure position = P1 (56°20'N, 008°12'W) Arrival position = P2 (52°12'N, 057°10'W)

Solution

To solve this problem, we need to calculate the following:

  1. Great Circle Distance: This is the shortest distance between two points on the surface of a sphere. It can be calculated using the haversine formula or the spherical law of cosines.
  2. Initial Course (or Bearing): This is the angle from the starting point to the endpoint at the departure position.
  3. Final Course (or Bearing): This is the angle from the arrival position back towards the departure position.

Given:

  • Departure Position P1P_1: 5620N,00812W56^\circ 20' \text{N}, 008^\circ 12' \text{W}
  • Arrival Position P2P_2: 5212N,05710W52^\circ 12' \text{N}, 057^\circ 10' \text{W}

Let's start by converting these coordinates into decimal degrees and proceed with the calculations:

1. Convert Coordinates to Decimal Degrees

  • P1P_1:

    • Latitude: 562056^\circ 20' = 56+2060=56.333356 + \frac{20}{60} = 56.3333^\circ N
    • Longitude: 00812008^\circ 12' = (8+1260)=8.2- (8 + \frac{12}{60}) = -8.2^\circ W
  • P2P_2:

    • Latitude: 521252^\circ 12' = 52+1260=52.252 + \frac{12}{60} = 52.2^\circ N
    • Longitude: 05710057^\circ 10' = (57+1060)=57.1667- (57 + \frac{10}{60}) = -57.1667^\circ W

2. Great Circle Distance Calculation

Using the spherical law of cosines formula: d=Rarccos(sinϕ1sinϕ2+cosϕ1cosϕ2cos(λ2λ1))d = R \cdot \arccos(\sin \phi_1 \cdot \sin \phi_2 + \cos \phi_1 \cdot \cos \phi_2 \cdot \cos(\lambda_2 - \lambda_1)) where:

  • RR is the Earth’s radius (mean radius = 6,371 km),
  • ϕ1\phi_1 and ϕ2\phi_2 are the latitudes of P1P_1 and P2P_2 in radians,
  • λ1\lambda_1 and λ2\lambda_2 are the longitudes of P1P_1 and P2P_2 in radians.

3. Initial and Final Course Calculations

For the initial bearing θ1\theta_1 from P1P_1 and the final bearing θ2\theta_2 approaching P2P_2, we use: θ=arctan(sin(Δλ)cosϕ2cosϕ1sinϕ2sinϕ1cosϕ2cos(Δλ))\theta = \arctan \left( \frac{\sin(\Delta \lambda) \cdot \cos \phi_2}{\cos \phi_1 \cdot \sin \phi_2 - \sin \phi_1 \cdot \cos \phi_2 \cdot \cos(\Delta \lambda)} \right) where Δλ=λ2λ1\Delta \lambda = \lambda_2 - \lambda_1.

I'll perform these calculations for an accurate solution.The results for the given positions are as follows:

  1. Great Circle Distance: Approximately 3144 km
  2. Initial Course (Bearing) from the departure position: 77.4277.42^\circ
  3. Final Course (Bearing) approaching the arrival position: 298.02298.02^\circ

Would you like a detailed explanation of any part of these calculations, or do you have any other questions?

Here are some related questions that expand on this topic:

  1. How is the great circle distance different from a straight line distance?
  2. What other methods can be used to calculate the distance between two points on the Earth’s surface?
  3. Why is it necessary to convert coordinates to radians when calculating distances and bearings?
  4. How can we verify if these bearings are correct using different methods?
  5. What would be the impact of Earth's ellipsoidal shape on these calculations?

Tip: When dealing with navigation problems, always ensure to check if your results make sense directionally and distance-wise, especially for long distances where the curvature of the Earth has a significant impact.

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Math Problem Analysis

Mathematical Concepts

Trigonometry
Spherical Geometry
Great Circle Distance
Bearings and Courses

Formulas

Spherical law of cosines for distance: d = R * arccos(sin φ1 * sin φ2 + cos φ1 * cos φ2 * cos(λ2 - λ1))
Formula for initial and final bearing: θ = arctan((sin Δλ * cos φ2) / (cos φ1 * sin φ2 - sin φ1 * cos φ2 * cos Δλ))

Theorems

Spherical Law of Cosines
Bearing Calculation Formula

Suitable Grade Level

College-level or Advanced High School (Grades 11-12)