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The question asks to calculate the gravitational potential energy (\( E_p \)) of the Helios Prototype (HP01) at a height of 29,500 meters using the formula:

\[
E_p = mgh
\]

where:
- \( m \) is the mass of the aircraft, which is 600 kg,
- \( g \) is the gravitational acceleration, given as \( 10 \, \text{m/s}^2 \),
- \( h \) is the height, which is 29,500 meters.

Now, let’s calculate the potential energy.

\[
E_p = 600 \times 10 \times 29,500
\]The gravitational potential energy of the Helios Prototype (HP01) at a height of 29,500 meters is \( 177,000,000 \, \text{Joules} \) (J).

Would you like further details or have any questions? Here are five related questions to deepen understanding:

1. How would the potential energy change if the aircraft’s mass were doubled?
2. How is gravitational potential energy related to kinetic energy when the object falls?
3. How does the value of gravitational acceleration \( g \) affect the calculation?
4. What happens to potential energy as an object’s height approaches zero?
5. Can you derive the relationship between potential energy and work done against gravity?

**Tip:** Gravitational potential energy is directly proportional to both mass and height—doubling either one will double the energy.

Kira tenaga keupayaan graviti pesawat Helios Prototype (HP01) pada ketinggian 29,500m menggunakan rumus: Tenaga Keupayaan = mgh (g = 10m/s^2)

Calculate the gravitational potential energy of the Helios Prototype (HP01) at a height of 29,500 meters. Using the formula Ep = mgh, with mass = 600kg, height = 29,500m, and gravitational acceleration g = 10 m/s², this problem explores key concepts of energy in physics. Suitable for high school students.

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