Math Problem Statement

Question content area top left Part 1 Use the graph of y equals x squared to graph the quadratic function. f left parenthesis x right parenthesis equals left parenthesis x plus 6 right parenthesis squared plus 2 Question content area bottom left Part 1 Use the graphing tool to graph the function.

. . . Question content area right Part 1 -10 -8 -6 -4 -2 2 4 6 8 10 -10 -8 -6 -4 -2 2 4 6 8 10 x y

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Solution

To graph the quadratic function f(x)=(x+6)2+2f(x) = (x + 6)^2 + 2, you'll follow these steps based on the transformation of the basic quadratic function y=x2y = x^2:

1. Identify the Transformations:

  • Horizontal Shift: The x+6x + 6 inside the squared term indicates a horizontal shift. Specifically, the graph of y=x2y = x^2 will shift 6 units to the left.
  • Vertical Shift: The +2+2 outside the squared term indicates a vertical shift. The graph will move 2 units up.

2. Determine the Vertex:

  • The vertex of the basic function y=x2y = x^2 is at the origin (0,0)(0, 0).
  • After the transformations, the vertex of f(x)=(x+6)2+2f(x) = (x + 6)^2 + 2 will be shifted to the point (6,2)(-6, 2).

3. Plot the Vertex:

  • Start by plotting the vertex at (6,2)(-6, 2).

4. Plot Additional Points:

  • Choose a few x-values around the vertex and calculate the corresponding y-values.
  • For example:
    • If x=7x = -7: f(7)=(7+6)2+2=12+2=3f(-7) = (-7 + 6)^2 + 2 = 1^2 + 2 = 3.
    • If x=5x = -5: f(5)=(5+6)2+2=12+2=3f(-5) = (-5 + 6)^2 + 2 = 1^2 + 2 = 3.
    • If x=4x = -4: f(4)=(4+6)2+2=22+2=6f(-4) = (-4 + 6)^2 + 2 = 2^2 + 2 = 6.

5. Sketch the Parabola:

  • Connect the points with a smooth curve, ensuring that it opens upwards, as the coefficient of x2x^2 is positive.

6. Graph the Function:

  • Use the graphing tool to plot the points and draw the curve.

Graph Summary:

  • Vertex: (6,2)(-6, 2)
  • Direction: Opens upwards.
  • Shifts: Left 6 units, up 2 units.

Would you like more details or have any questions?

Follow-up Questions:

  1. How would the graph change if the equation was f(x)=(x6)2+2f(x) = (x - 6)^2 + 2?
  2. What is the axis of symmetry for the function f(x)=(x+6)2+2f(x) = (x + 6)^2 + 2?
  3. How does the coefficient of the squared term affect the graph's shape?
  4. What are the key differences between the graph of f(x)=x2f(x) = x^2 and f(x)=(x+6)2+2f(x) = (x + 6)^2 + 2?
  5. Can you derive the function's formula from a different vertex and transformation?

Tip: Always start by identifying the vertex and direction of the parabola when graphing quadratic functions.

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Math Problem Analysis

Mathematical Concepts

Quadratic Functions
Vertex Form
Transformations of Functions

Formulas

Vertex form of a quadratic function: f(x) = (x + h)^2 + k

Theorems

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Suitable Grade Level

Grades 9-12