The equation in the image is $y + 2 = \frac{1}{6}(x + 3)$.

To graph this, let's first rewrite it in slope-intercept form $y = mx + b$, where $m$ is the slope and $b$ is the y-intercept.

1. Start with the given equation: $y + 2 = \frac{1}{6}(x + 3)$
2. Subtract 2 from both sides to isolate $y$: $y = \frac{1}{6}(x + 3) - 2$
3. Distribute $\frac{1}{6}$ on the right side: $y = \frac{1}{6}x + \frac{3}{6} - 2$
4. Simplify the constants: $y = \frac{1}{6}x + \frac{1}{2} - 2$ $y = \frac{1}{6}x - \frac{3}{2}$

Now we can see that the slope $m$ is $\frac{1}{6}$ and the y-intercept $b$ is $-\frac{3}{2}$.

Graphing Instructions:

1. Plot the y-intercept: Start by marking the point $(0, -\frac{3}{2})$ on the graph, which is at $(0, -1.5)$.
2. Use the slope: From the point $(0, -1.5)$, move up 1 unit and to the right 6 units to find another point on the line. This corresponds to a rise of 1 and a run of 6, as the slope is $\frac{1}{6}$.
3. Draw the line: After plotting a couple of points, draw a straight line through them.

Would you like help with another part of this question or any clarification?

Here are 5 related questions you might explore:

1. How do you find the slope and y-intercept of a linear equation?
2. What does the slope of $\frac{1}{6}$ tell you about the graph?
3. How do you graph a line from an equation in standard form?
4. How would the graph change if the slope was negative?
5. How can you convert between standard form and slope-intercept form?

Tip: When graphing lines, always plot the y-intercept first, then use the slope to find additional points. This makes graphing quicker and more accurate.