To graph the equation $-x + y = 5$, you can rearrange it into slope-intercept form $y = mx + b$. This gives:

$y = x + 5$

Steps to graph:

1. Find the y-intercept: Set $x = 0$: $y = 0 + 5 = 5$ So the point is $(0, 5)$.

2. Find the x-intercept: Set $y = 0$: $0 = x + 5 \implies x = -5$ So the point is $(-5, 0)$.

3. Plot the points: Plot $(0, 5)$ and $(-5, 0)$ on the graph.

4. Draw the line: Connect these points with a straight line, extending it in both directions.

If you have graphing software or a physical graph, you can drag the dots at $(0, 5)$ and $(-5, 0)$ to visualize the line.

Would you like any further details or have any questions about this process? Here are some related questions you might consider:

1. How do you find the slope of a linear equation?
2. What does the slope represent in a graph?
3. Can you explain how to graph a different linear equation?
4. How would the graph change if we had $y = -x + 5$?
5. What are the characteristics of parallel and perpendicular lines?

Tip: Always check your intercepts; they are crucial for accurately drawing linear graphs.