Math Problem Statement

Given the linear equation y = (2/3)x + 2, fill in the table with x and y values and graph the equation on the provided grid.

Solution

The image shows a linear equation y=23x+2y = \frac{2}{3}x + 2, a table with empty xx and yy values, and a coordinate plane grid for graphing. To complete the table and graph the equation, we can choose specific values for xx, compute the corresponding values for yy, and plot them.

Step-by-Step Process:

  1. Choose xx-values: Let's pick three easy values for xx, such as -3, 0, and 3.

  2. Substitute into the equation:

    • For x=3x = -3: y=23(3)+2=2+2=0y = \frac{2}{3}(-3) + 2 = -2 + 2 = 0
    • For x=0x = 0: y=23(0)+2=0+2=2y = \frac{2}{3}(0) + 2 = 0 + 2 = 2
    • For x=3x = 3: y=23(3)+2=2+2=4y = \frac{2}{3}(3) + 2 = 2 + 2 = 4
  3. Complete the table:

xxyy
-30
02
34
  1. Plot the points on the grid:
    • Plot the points (-3, 0), (0, 2), and (3, 4).
    • Draw a straight line through these points to represent the equation y=23x+2y = \frac{2}{3}x + 2.

Would you like further details or have any questions? Here are some related questions to explore:

  1. How do you calculate the slope from the equation y=23x+2y = \frac{2}{3}x + 2?
  2. What does the value 2 represent in the equation y=23x+2y = \frac{2}{3}x + 2?
  3. Can you choose other values for xx to complete the table?
  4. What happens if you substitute negative or larger numbers for xx?
  5. How can you determine the y-intercept from the equation?

Tip: The slope in the equation y=23x+2y = \frac{2}{3}x + 2 tells you that for every 3 units you move right on the x-axis, the y-value increases by 2.

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Math Problem Analysis

Mathematical Concepts

Linear Equations
Coordinate Graphing
Slope-Intercept Form

Formulas

y = mx + b

Theorems

Slope-Intercept Theorem

Suitable Grade Level

Grades 6-8