To solve this problem, we need to determine which of the given points lies in the region where the inequality $y > 2x + 3$ is true.

Step 1: Understand the Inequality

The inequality $y > 2x + 3$ describes a region above the line $y = 2x + 3$ on a graph.

Step 2: Substitute the Coordinates into the Inequality

We will substitute each point into the inequality to see if it satisfies the condition $y > 2x + 3$.

1. Point (2,2): $y = 2 \quad \text{and} \quad 2x + 3 = 2(2) + 3 = 4 + 3 = 7$ $2 > 7$ is false.

2. Point (2,-2): $y = -2 \quad \text{and} \quad 2x + 3 = 2(2) + 3 = 4 + 3 = 7$ $-2 > 7$ is false.

3. Point (-2,2): $y = 2 \quad \text{and} \quad 2x + 3 = 2(-2) + 3 = -4 + 3 = -1$ $2 > -1$ is true.

4. Point (-2,-2): $y = -2 \quad \text{and} \quad 2x + 3 = 2(-2) + 3 = -4 + 3 = -1$ $-2 > -1$ is false.

5. Point (2,3): $y = 3 \quad \text{and} \quad 2x + 3 = 2(2) + 3 = 4 + 3 = 7$ $3 > 7$ is false.

Conclusion:

The only point that satisfies the inequality $y > 2x + 3$ is (c) (-2,2).

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Would you like more details or have any questions? Here are some related questions to consider:

1. What is the slope-intercept form of a linear equation?
2. How do you graph a linear inequality on a coordinate plane?
3. What changes if the inequality is $y \geq 2x + 3$ instead of $y > 2x + 3$?
4. How do you find the x- and y-intercepts of the line $y = 2x + 3$?
5. What does the inequality $y < 2x + 3$ represent on the graph?

Tip: When graphing an inequality, remember that if the inequality is strict (i.e., $>$ or $<$), the boundary line is dashed. If it is non-strict (i.e., $\geq$ or $\leq$), the boundary line is solid.