Math Problem Statement

Use the given information to graph the function • domain of f(x) is (−∞,∞) • limx→−∞ f(x) → −∞ and limx→∞ f(x) → ∞ • f(0) = 7 • f ′ (−1) = 0 and f ′ (1) = 0 • f ′ (x) > 0 on (−∞,−1)∪(1,∞) • f ′ (x) < 0 on (−1,1) • f ′′(x) > 0 on (0,∞) • f ′′(x) < 0 on (−∞,0)

Solution

Let's break down the given information step-by-step and use it to sketch the graph of the function f(x)f(x):

1. Domain:

The domain of f(x)f(x) is (,)(-\infty, \infty), meaning the function is defined for all real numbers.

2. Behavior at infinity:

  • As xx \to -\infty, f(x)f(x) \to -\infty. This tells us that the function decreases without bound on the left.
  • As xx \to \infty, f(x)f(x) \to \infty. This tells us that the function increases without bound on the right.

3. Point of interest: f(0)=7f(0) = 7:

The function passes through the point (0,7)(0, 7). This is a key point on the graph.

4. Critical points:

  • f(x)=0f'(x) = 0 at x=1x = -1 and x=1x = 1. These are possible local extrema, i.e., where the function may have a local maximum or minimum.
  • f(x)>0f'(x) > 0 on (,1)(1,)(-\infty, -1) \cup (1, \infty). This indicates that the function is increasing on these intervals.
  • f(x)<0f'(x) < 0 on (1,1)(-1, 1). This indicates that the function is decreasing on this interval.

5. Concavity:

  • f(x)<0f''(x) < 0 on (,0)(-\infty, 0). This tells us the graph is concave down (shaped like a hill) on the left side of x=0x = 0.
  • f(x)>0f''(x) > 0 on (0,)(0, \infty). This tells us the graph is concave up (shaped like a bowl) on the right side of x=0x = 0.

Step-by-step sketch construction:

  1. From left to right:

    • The function starts decreasing as xx \to -\infty since limxf(x)=\lim_{x \to -\infty} f(x) = -\infty.
    • The function increases on (,1)(-\infty, -1), so the slope is positive in this region.
    • At x=1x = -1, there's a critical point, which is a local maximum since f(x)f'(x) changes from positive to negative at this point.
    • The function decreases on (1,1)(-1, 1), with a critical point at x=1x = 1, which is a local minimum because f(x)f'(x) changes from negative to positive at this point.
  2. At x=0x = 0:

    • We know f(0)=7f(0) = 7, so the function passes through the point (0,7)(0, 7).
    • The function is concave down on (,0)(-\infty, 0) and concave up on (0,)(0, \infty), so there's an inflection point at x=0x = 0.
  3. To the right:

    • The function increases on (1,)(1, \infty), and since limxf(x)=\lim_{x \to \infty} f(x) = \infty, the function will keep increasing without bound as xx \to \infty.

Conclusion:

  • The graph starts at negative infinity for xx \to -\infty, increases until x=1x = -1, where there's a local maximum.
  • It then decreases to a local minimum at x=1x = 1, passing through the point (0,7)(0, 7), where the concavity changes.
  • The graph then increases indefinitely as xx \to \infty, while maintaining concave up behavior.

If you need an actual visual of this graph, I can generate one for you. Would you like that?

Expanding Questions:

  1. How do concavity and inflection points affect the shape of a graph?
  2. Can you explain how the first derivative test helps identify local extrema?
  3. What is the significance of a function’s behavior at infinity?
  4. How does knowing the critical points help when sketching a graph?
  5. What additional information could be helpful for refining this graph sketch?

Tip:

To fully understand how a function behaves, always analyze both the first and second derivatives. The first derivative reveals increasing/decreasing behavior, while the second derivative gives insight into concavity.

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Math Problem Analysis

Mathematical Concepts

Calculus
Function Behavior
Derivatives
Concavity

Formulas

First Derivative Test
Second Derivative Test
Limits

Theorems

First Derivative Test for Local Extrema
Second Derivative Test for Concavity

Suitable Grade Level

Grades 11-12 (Advanced Calculus)