Math Problem Statement

Which of the following could be the graph of y=x^4-〖5x〗^2+4?

Solution

To determine which graph corresponds to the function y=x45x2+4y = x^4 - 5x^2 + 4, let's first analyze its general shape and key features.

1. General Shape (Even degree polynomial):

The highest degree of the function is 4, which means the graph will have a general "U" shape. Specifically:

  • As xx \to \infty, yy \to \infty (since x4x^4 dominates at large values of xx).
  • As xx \to -\infty, yy \to \infty (since x4x^4 also dominates at large negative values of xx).

Thus, the ends of the graph both point upwards.

2. Symmetry:

Since the function only has even powers of xx (no odd terms), the graph will be symmetric about the y-axis. This is because for every positive xx, f(x)=f(x)f(x) = f(-x).

3. Intercepts:

  • Y-intercept: Set x=0x = 0. y=045(0)2+4=4y = 0^4 - 5(0)^2 + 4 = 4 So, the y-intercept is at (0,4)(0, 4).

  • X-intercepts (roots): Set y=0y = 0 and solve the equation x45x2+4=0x^4 - 5x^2 + 4 = 0. Let z=x2z = x^2, then the equation becomes: z25z+4=0z^2 - 5z + 4 = 0 Solving this quadratic equation: z=5±25162=5±32z = \frac{5 \pm \sqrt{25 - 16}}{2} = \frac{5 \pm 3}{2} So, z=4z = 4 or z=1z = 1.

    Since z=x2z = x^2, we have two cases:

    • x2=4x^2 = 4, which gives x=±2x = \pm 2,
    • x2=1x^2 = 1, which gives x=±1x = \pm 1.

    Thus, the x-intercepts are x=2,1,1,2x = -2, -1, 1, 2, and the corresponding points are (2,0),(1,0),(1,0),(2,0)(-2, 0), (-1, 0), (1, 0), (2, 0).

4. Turning Points:

To find the critical points, we differentiate y=x45x2+4y = x^4 - 5x^2 + 4: dydx=4x310x\frac{dy}{dx} = 4x^3 - 10x Setting this equal to 0 to find the critical points: 4x(x22.5)=04x(x^2 - 2.5) = 0 Thus, x=0x = 0 or x=±2.5x = \pm \sqrt{2.5}.

  • x=0x = 0 is a critical point, and solving for ±2.5\pm \sqrt{2.5} will give us the x-coordinates of the other turning points.

Conclusion:

The graph is symmetric about the y-axis, has a minimum at x=0x = 0, crosses the x-axis at x=2,1,1,2x = -2, -1, 1, 2, and extends upwards at the far left and right.

Given this analysis, you can compare these features with the options for the graph of the function. Does this make sense, and do you want more details about the graph's turning points?


Here are some related questions:

  1. How would you solve for turning points of a higher degree polynomial?
  2. Can you explain how the symmetry of even-powered functions affects their graph?
  3. What happens to the shape of a polynomial graph when higher-order terms dominate?
  4. Why does the function have 4 x-intercepts, and how does that relate to its degree?
  5. What role do y-intercepts play in determining a graph’s key features?

Tip: To sketch a polynomial function, always start with finding intercepts and considering the behavior at extremes (large positive and negative x-values).

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Math Problem Analysis

Mathematical Concepts

Polynomial Functions
Graph Symmetry
Roots of Equations
Turning Points

Formulas

y = x^4 - 5x^2 + 4
Quadratic Formula: x = (-b ± √(b^2 - 4ac)) / 2a
First Derivative: dy/dx = 4x^3 - 10x

Theorems

Fundamental Theorem of Algebra
Symmetry of Even Functions

Suitable Grade Level

Grades 10-12