To graph the linear function $y = -9x + 5$, we can follow these steps using the slope and y-intercept:

1. Y-intercept: The y-intercept is $5$, which means the line crosses the y-axis at the point $(0, 5)$. Plot this point on the graph.

2. Slope: The slope is $-9$, meaning for every 1 unit you move to the right (along the x-axis), the value of $y$ decreases by 9 units. This can be represented as a rise-over-run of $\frac{-9}{1}$.

3. Plot another point using the slope: From $(0, 5)$, move 1 unit to the right (along the x-axis) and then 9 units down (because the slope is negative). This will give you the point $(1, -4)$.

4. Draw the line: After plotting the two points, $(0, 5)$ and $(1, -4)$, draw a straight line through them to represent the function.

You can now input these points into your tool and submit the graph.

Let me know if you'd like further details or assistance!

Here are five related questions:

1. How do you find the slope of a line from its equation in slope-intercept form?
2. What does the y-intercept represent in a linear equation?
3. How does changing the slope affect the steepness of the line?
4. How can you graph a line if given only two points?
5. What is the significance of a negative slope in a linear function?

Tip: When graphing a line, always start with the y-intercept, then use the slope to find additional points on the graph.