The equation of the line given is $y = \frac{5}{7}x - 10$, which is in slope-intercept form, $y = mx + b$, where:

• The slope $m = \frac{5}{7}$.
• The y-intercept $b = -10$.

To graph this line:

1. Start by plotting the y-intercept at $(0, -10)$ on the graph. This is where the line crosses the y-axis.
2. Use the slope to determine another point. The slope $\frac{5}{7}$ means "rise over run" (i.e., move 5 units up for every 7 units you move to the right). So, from the y-intercept $(0, -10)$, move 7 units to the right and 5 units up to get to the point $(7, -5)$.
3. Plot this second point $(7, -5)$, and draw a straight line through the two points.

These steps will give you the line that represents the equation.

Would you like me to provide additional information or clarifications?

Related questions:

1. How do you identify the slope and y-intercept from an equation?
2. What is the significance of the slope in real-world applications?
3. How do you graph a line using just two points?
4. How do you calculate the slope between two points on a graph?
5. What happens to the graph if the slope is negative?

Tip: Remember, the slope tells you how steep the line is. If the slope is positive, the line will rise from left to right; if the slope is negative, the line will fall from left to right.