Math Problem Statement

Sketch two periods of the graph of the function p(x)=tan(x−π4) . Identify the stretching factor, period, and asymptotes.

Solution

To sketch the graph of the function p(x)=tan(xπ4)p(x) = \tan(x - \frac{\pi}{4}), let's break down the problem step by step:

1. General Properties of the Tangent Function:

The general tangent function is tan(x)\tan(x). For this function, the important properties are:

  • Period: The period of tan(x)\tan(x) is π\pi, meaning that the graph repeats every π\pi units along the x-axis.
  • Asymptotes: The asymptotes of tan(x)\tan(x) occur where the function is undefined, i.e., at x=π2+nπx = \frac{\pi}{2} + n\pi, where nn is an integer.

2. Effect of the Transformation xπ4x - \frac{\pi}{4}:

The transformation p(x)=tan(xπ4)p(x) = \tan(x - \frac{\pi}{4}) represents a horizontal shift of the graph of tan(x)\tan(x) by π4\frac{\pi}{4} units to the right. This means:

  • The asymptotes will shift from x=π2+nπx = \frac{\pi}{2} + n\pi to x=π4+nπx = \frac{\pi}{4} + n\pi.
  • The period remains π\pi because the coefficient of xx inside the tangent function is 1 (no horizontal stretching).

3. Key Features:

  • Period: The period of the graph is still π\pi, as the transformation only involves a shift, not a stretching or compressing.
  • Asymptotes: The vertical asymptotes of the function will occur at: x=π4+nπ,nZx = \frac{\pi}{4} + n\pi, \quad n \in \mathbb{Z} So, the first two asymptotes are at x=π4x = \frac{\pi}{4} and x=5π4x = \frac{5\pi}{4}.

4. Sketching Two Periods:

  • For the first period (from x=π4x = \frac{\pi}{4} to x=5π4x = \frac{5\pi}{4}):

    • The tangent function will cross through x=π2x = \frac{\pi}{2}, the midpoint between the asymptotes.
    • The graph will start from the asymptote at x=π4x = \frac{\pi}{4}, rise to the midpoint, and then approach the asymptote at x=5π4x = \frac{5\pi}{4}.
  • For the second period (from x=5π4x = \frac{5\pi}{4} to x=9π4x = \frac{9\pi}{4}):

    • The behavior is similar: the graph rises from x=5π4x = \frac{5\pi}{4}, reaches the midpoint at x=7π4x = \frac{7\pi}{4}, and approaches the asymptote at x=9π4x = \frac{9\pi}{4}.

5. Final Graph:

You will see a standard tangent shape, but shifted to the right by π4\frac{\pi}{4}.

Summary of Key Features:

  • Period: π\pi (unchanged).
  • Asymptotes: Occur at x=π4+nπx = \frac{\pi}{4} + n\pi, where nn is an integer.
  • Stretching Factor: There is no stretching factor, as the coefficient of xx is 1.

Would you like a visual representation or any further explanation on the behavior of this function?

Related Questions:

  1. How does a horizontal shift affect the tangent function?
  2. What happens to the period of a tangent function if there's a coefficient inside the argument, like tan(kx)\tan(kx)?
  3. How do you find the asymptotes of the function tan(x+c)\tan(x + c)?
  4. What happens if the function is stretched vertically (e.g., atan(x)a \tan(x))?
  5. Can you graph other trigonometric functions, like sine and cosine, with similar transformations?

Tip: To graph any transformation of tan(x)\tan(x), always start by identifying the asymptotes, then plot the midpoints where the function crosses the x-axis, and finally sketch the standard shape of the tangent curve between them.

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Math Problem Analysis

Mathematical Concepts

Trigonometry
Graph Transformations
Tangent Function

Formulas

p(x) = tan(x - π/4)
Period of tangent function: π
Asymptotes at x = (π/2 + nπ) for the general tangent function

Theorems

Periodic behavior of the tangent function
Horizontal shift properties

Suitable Grade Level

Grades 9-12