Math Problem Statement
Solution
Let's go through the problem together based on the graph of and the questions:
(a) At which -values (if any) is not differentiable? Explain.
A function is not differentiable at points where:
- There is a sharp corner or cusp.
- The function is discontinuous.
- The slope is vertical (infinite).
From the graph, look for any sharp corners or discontinuities in .
(b) For which -values (if any) do we have ? Explain.
To find where , look for points where the tangent line to the graph is horizontal. These points correspond to local maxima, minima, or inflection points.
(c) Which value is greater, or ? How do you know?
We are comparing the slopes of the tangent lines at and . Determine which slope is steeper or has a larger magnitude based on the graph's steepness at these points.
(d) Use the graph to estimate .
To estimate , look at the slope of the tangent line at , and approximate its value.
Would you like me to walk you through the steps for each part of the solution in more detail, or clarify any specific part?
Here are 5 related questions:
- What are the conditions for a function to be differentiable at a point?
- How do critical points relate to ?
- How can you tell if the slope of a function is positive, negative, or zero just by looking at the graph?
- What are the geometric interpretations of the derivative of a function?
- Why might be greater or smaller than based on graph behavior?
Tip: When analyzing a graph for differentiability, always check for sharp turns, cusps, and vertical tangents.
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Math Problem Analysis
Mathematical Concepts
Differentiability
Critical Points
Graph Analysis
Tangent Slopes
Formulas
g'(t) = 0 at critical points
Derivative as slope of the tangent line
Theorems
Differentiability implies continuity
The Mean Value Theorem (implied by slope calculations)
Suitable Grade Level
Grades 10-12 (Calculus)
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