Math Problem Statement

Sketch the graph of the given equation over the interval

​[minus−2piπ​,

2piπ​].

yequals=Bold coscosleft parenthesis x minus StartFraction pi Over 12 EndFraction right parenthesisx−π12

show me work

Solution

The graph of the function y=cos(xπ12)y = \cos \left( x - \frac{\pi}{12} \right) is shown above. It depicts the cosine wave, shifted to the right by π12\frac{\pi}{12}, over the interval [2π,2π][-2\pi, 2\pi]. The wave maintains its typical oscillation between 1 and -1, with critical points shifted accordingly.

Let me know if you need any clarifications or further details!

Here are 5 related questions you can explore:

  1. How would the graph change if the function was y=cos(x+π12)y = \cos(x + \frac{\pi}{12})?
  2. What effect does modifying the amplitude have on the cosine function?
  3. How would the period of the function change if it was y=cos(2x)y = \cos(2x)?
  4. Can you describe the graph of y=sin(xπ12)y = \sin\left( x - \frac{\pi}{12} \right)?
  5. What happens to the graph if we introduce a vertical shift, such as y=cos(xπ12)+1y = \cos\left( x - \frac{\pi}{12} \right) + 1?

Tip: The phase shift affects the horizontal position of the wave but does not alter the amplitude or period.

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Math Problem Analysis

Mathematical Concepts

Trigonometry
Graphing Trigonometric Functions
Phase Shifts

Formulas

y = cos(x - π/12)

Theorems

Cosine function properties
Phase shift theorem

Suitable Grade Level

Grades 10-12