Math Problem Statement

Suppose that the function f is defined, for all real numbers, as follows: f(x) = { x - 2 if x < -2; 3x + 2 if x ≥ -2 }. Graph the function f. Then determine whether or not the function is continuous.

Solution

Here is the graph of the function f(x)f(x). As we discussed earlier, the function is continuous at x=2x = -2 because the left-hand limit, right-hand limit, and the function's value at x=2x = -2 all agree at 4-4, which can be seen on the graph (marked by the red dot at (2,4)(-2, -4)).

Would you like further clarification on this, or do you have any other questions?

Here are 5 related questions for further exploration:

  1. How do you determine if a piecewise function is differentiable at the boundary point?
  2. What is the derivative of f(x)f(x) for each piece of this piecewise function?
  3. Can a function be continuous but not differentiable at a certain point? If so, provide examples.
  4. How would you modify this function to make it discontinuous at x=2x = -2?
  5. How do limits play a role in determining continuity for more complex piecewise functions?

Tip: When analyzing continuity, always check the limits from both the left and right at any potential points of discontinuity.

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Math Problem Analysis

Mathematical Concepts

Piecewise Functions
Limits
Continuity

Formulas

Limit as x approaches a point
f(x) for x < -2: x - 2
f(x) for x ≥ -2: 3x + 2

Theorems

Continuity theorem: A function is continuous at a point if the left-hand limit, right-hand limit, and function value all agree.

Suitable Grade Level

Grades 11-12