Math Problem Statement

Analyze the graph of the function y = f(x) and determine f(6), lim x->4 f(x), lim x->1^+ f(x), and lim x->3 f(x).

Solution

Let's analyze the graph of y=f(x)y = f(x) to answer the given questions.

  1. f(6)=4f(6) = 4 (already provided).

Now, let's address the limit questions:

  1. limx4f(x)\lim_{x \to 4} f(x):

    The graph shows a discontinuity at x=4x = 4. From the left side of x=4x = 4 (as x4x \to 4^-), the value of f(x)f(x) approaches 1. From the right side (as x4+x \to 4^+), the value of f(x)f(x) approaches 3. Since the left-hand limit and the right-hand limit are not equal, the overall limit does not exist.

    Therefore, limx4f(x)=DNE\lim_{x \to 4} f(x) = \text{DNE}.

  2. limx1+f(x)\lim_{x \to 1^+} f(x):

    Looking at the graph from the right of x=1x = 1, the value of f(x)f(x) is 5. Since the graph approaches x=1x = 1 from the right with no discontinuity, the right-hand limit exists and equals 5.

    Therefore, limx1+f(x)=5\lim_{x \to 1^+} f(x) = 5.

  3. limx3f(x)\lim_{x \to 3} f(x):

    At x=3x = 3, there is also a discontinuity. From the left of x=3x = 3, the value of f(x)f(x) approaches 2, and from the right, the value of f(x)f(x) approaches 4. Since these values are different, the limit does not exist.

    Therefore, limx3f(x)=DNE\lim_{x \to 3} f(x) = \text{DNE}.

Summary of Answers:

  • f(6)=4f(6) = 4
  • limx4f(x)=DNE\lim_{x \to 4} f(x) = \text{DNE}
  • limx1+f(x)=5\lim_{x \to 1^+} f(x) = 5
  • limx3f(x)=DNE\lim_{x \to 3} f(x) = \text{DNE}

Would you like further details or explanations on any of these steps?

Here are 5 additional questions that expand on this:

  1. What is limx5f(x)\lim_{x \to 5} f(x)?
  2. What is the value of f(0)f(0)?
  3. Is f(x)f(x) continuous at x=2x = 2?
  4. What is the left-hand limit limx1f(x)\lim_{x \to 1^-} f(x)?
  5. How many discontinuities does the function f(x)f(x) have on the interval [0,9][0,9]?

Tip: Limits involving discontinuities are best handled by checking the behavior from both sides (left and right) to confirm if they match.

Ask a new question for Free

By Image

Drop file here or Click Here to upload

Math Problem Analysis

Mathematical Concepts

Functions
Limits
Continuity
Graph Analysis

Formulas

-

Theorems

Limit existence theorem
Discontinuity in functions

Suitable Grade Level

Grades 11-12 (High School Calculus)