Math Problem Statement

The image contains several geometry problems where the user is asked to determine if lines are parallel and solve for variables. Examples include applying the Triangle Proportionality Theorem and properties of transversals in parallel lines.

Solution

I see the uploaded image contains several math problems related to geometry and solving for variables. Let’s address them one by one:


Problem 8: Determine if STST is parallel to PRPR.

To determine if STST is parallel to PRPR, we need to check if the triangle adheres to the Triangle Proportionality Theorem, which states that if a line parallel to one side of a triangle divides the other two sides proportionally, then the line is parallel to the third side.

The triangle dimensions are:

  • SP=7,PT=10,PR=16SP = 7, PT = 10, PR = 16.

Using proportions: SPPT=710,STPR=11.216.\frac{SP}{PT} = \frac{7}{10}, \quad \frac{ST}{PR} = \frac{11.2}{16}.

Check: 710=0.7,11.216=0.7.\frac{7}{10} = 0.7, \quad \frac{11.2}{16} = 0.7. Since these proportions are equal, STST is parallel to PRPR.


Problem 10: Determine if STST is parallel to PRPR.

Here the triangle dimensions are:

  • SP=19,PT=38,PR=52SP = 19, PT = 38, PR = 52.

Using proportions: SPPT=1938=0.5,STPR=2A52.\frac{SP}{PT} = \frac{19}{38} = 0.5, \quad \frac{ST}{PR} = \frac{2A}{52}.

We need 2A2A to satisfy 2A52=0.5\frac{2A}{52} = 0.5: 2A=0.5×52=26so A=13.2A = 0.5 \times 52 = 26 \quad \text{so } A = 13.

Thus, if A=13A = 13, STST is parallel to PRPR.


Problem 11: Solve for xx.

The given diagram shows a transversal cutting two parallel lines, forming pairs of proportional segments. By the property of transversals: 2530=48x.\frac{25}{30} = \frac{48}{x}.

Cross-multiply: 25x=30×48.25x = 30 \times 48.

Simplify: 25x=1440x=144025=57.6.25x = 1440 \quad \Rightarrow \quad x = \frac{1440}{25} = 57.6.

So, x=57.6x = 57.6.


Problem 14: Solve for xx.

This involves solving for xx using the given segments of a triangle divided by a transversal.

The proportions are: x321=x127.\frac{x-3}{21} = \frac{x-1}{27}.

Cross-multiply: 27(x3)=21(x1).27(x - 3) = 21(x - 1).

Expand: 27x81=21x21.27x - 81 = 21x - 21.

Simplify: 6x=60x=10.6x = 60 \quad \Rightarrow \quad x = 10.

So, x=10x = 10.


Problem 15: Solve for xx.

Here we equate the ratios of the parallel lines: 7x1120=4x235.\frac{7x - 11}{20} = \frac{4x - 2}{35}.

Cross-multiply: 35(7x11)=20(4x2).35(7x - 11) = 20(4x - 2).

Expand: 245x385=80x40.245x - 385 = 80x - 40.

Simplify: 165x=345x=345165=2.09.165x = 345 \quad \Rightarrow \quad x = \frac{345}{165} = 2.09.

So, x2.09x \approx 2.09.


Would you like detailed explanations for any of these?
Here are five related questions to extend this:

  1. How is the Triangle Proportionality Theorem applied in different scenarios?
  2. What happens if proportions are not equal when solving for parallel lines?
  3. How does a transversal affect angle relationships in parallel lines?
  4. Can the proportionality rule be applied in non-triangular figures?
  5. What is the difference between corresponding and alternate angles in parallel lines?

Tip: Always double-check your setup of proportions to avoid simple errors in cross-multiplication!

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Math Problem Analysis

Mathematical Concepts

Triangle Proportionality Theorem
Ratios and Proportions
Properties of Transversals
Parallel Lines

Formulas

Proportionality: SP/PT = ST/PR
Cross-multiplication to solve ratios: a/b = c/d → ad = bc
Properties of parallel lines cut by a transversal: corresponding angles and proportional segments

Theorems

Triangle Proportionality Theorem

Suitable Grade Level

Grades 8-10