Math Problem Statement

The image contains three geometry problems involving a semicircle, a triangle, and a circle segment.

Solution

The image contains three geometry problems, with a focus on different concepts. Let's break them down one by one:

Problem 1:

A figure is provided, which seems to involve a semicircle and a triangle. The problem asks for the following:

  1. Area of the semicircle using the formula A=12πr2A = \frac{1}{2}\pi r^2, where rr is the radius.
  2. Area of the triangle using A=12×base×heightA = \frac{1}{2} \times \text{base} \times \text{height}.
  3. Area of the figure which involves subtracting the area of the triangle from the area of the semicircle.

Problem 2:

This problem involves a segment of a circle and asks for:

  1. Length of the arc using the formula L=θrL = \theta r, where θ\theta is the angle in radians and rr is the radius.
  2. Area of the segment which is typically calculated by subtracting the area of the triangle formed from the area of the sector.

Problem 3:

It involves solving a trigonometric identity or expression, likely requiring simplification or proving an equation involving trigonometric functions.


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Math Problem Analysis

Mathematical Concepts

Geometry
Area Calculation
Circle Segments
Trigonometry

Formulas

Area of a semicircle: A = (1/2)πr^2
Area of a triangle: A = (1/2) * base * height
Length of an arc: L = θr (where θ is in radians)
Area of a segment: (Area of sector) - (Area of triangle)

Theorems

Properties of circles
Trigonometric identities

Suitable Grade Level

Grades 10-12