Math Problem Statement

Given: BC bisects ∠ABD and m∠ABD = 52°. Prove: m∠ABC = 26°.

Solution

The image shows a geometry proof involving the bisecting of an angle. Let’s break it down:

Given:

  • BCBC bisects ABD\angle ABD.
  • mABD=52m \angle ABD = 52^\circ.

To Prove:

  • mABC=26m \angle ABC = 26^\circ.

Steps to the Proof:

  1. mABD=52m \angle ABD = 52^\circ — (Reason: Given)
  2. BCBC bisects ABD\angle ABD — (Reason: Given)
  3. mABC=mCBDm \angle ABC = m \angle CBD — (Reason: Definition of bisector)
  4. mABC+mCBD=mABDm \angle ABC + m \angle CBD = m \angle ABD — (Reason: Angle addition postulate)
  5. mABC+mABC=52m \angle ABC + m \angle ABC = 52^\circ — (Reason: Substitution property)

Now, for the final statement mABC+mABC=52m \angle ABC + m \angle ABC = 52^\circ, the correct reason to select would be substitution property, as it directly follows from substituting mCBDm \angle CBD with mABCm \angle ABC due to the bisector property.

Conclusion:

Since the angle was bisected, we divide the total angle into two equal parts. So:

2mABC=52    mABC=522=26.2m \angle ABC = 52^\circ \implies m \angle ABC = \frac{52^\circ}{2} = 26^\circ.

Would you like more details or have any questions? Here are five related questions to expand on this:

  1. How do you apply the angle addition postulate in more complex geometrical figures?
  2. Why is the definition of a bisector important in triangle congruence proofs?
  3. Can the substitution property be used for algebraic expressions involving angles?
  4. How can we prove that two angles are equal if a bisector is not given?
  5. What are other common properties involving bisectors in triangles?

Tip:

Always check if you can simplify the angles by looking for symmetries or properties like bisectors to make your proof easier.

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Math Problem Analysis

Mathematical Concepts

Geometry
Angle Bisectors
Angle Addition Postulate

Formulas

Angle Bisector: m∠ABC = m∠CBD
Angle Addition Postulate: m∠ABC + m∠CBD = m∠ABD

Theorems

Definition of Angle Bisector
Angle Addition Postulate
Substitution Property

Suitable Grade Level

Grades 8-10