Math Problem Statement

The figure given below consists of 3 identical squares overlapping in 2 rectangles marked P and Q. The areas of P and Q are equal. 1/8 of the whole figure is shaded. (a) If the area of rectangle P is 6 cm², what is the area of the whole figure? (b) Express the total areas of P and Q as a fraction of one square.

Solution

The question consists of two parts based on the given figure:

(a) If the area of rectangle PP is 6cm26 \, \text{cm}^2, what is the area of the whole figure?

Step-by-step solution:

  1. Assumptions:

    • The whole figure consists of 3 identical squares.
    • PP and QQ are equal in area.
    • 18\frac{1}{8} of the whole figure is shaded.
  2. Key observations:

    • The area of PP is 6cm26 \, \text{cm}^2. This implies Area of Q=6cm2\text{Area of } Q = 6 \, \text{cm}^2 as they are equal.
    • The rectangles PP and QQ are formed by overlapping sections of the squares.
  3. Fractional division of the area: Let the total area of one square be SS. Since there are 3 identical squares: Total Area of the whole figure=3S\text{Total Area of the whole figure} = 3S Given that 18\frac{1}{8} of the figure is shaded: Shaded Area=18×3S\text{Shaded Area} = \frac{1}{8} \times 3S This shaded area is part of PP and QQ.

  4. Relationship between P,Q,P, Q, and squares:

    • Since PP and QQ overlap parts of the squares and their combined area equals the shaded region: P+Q=18×3SP + Q = \frac{1}{8} \times 3S
  5. Solving for SS: Since P=Q=6cm2P = Q = 6 \, \text{cm}^2, the total area of P+QP + Q is: P+Q=6+6=12cm2P + Q = 6 + 6 = 12 \, \text{cm}^2 Substituting into the equation: 12=18×3S12 = \frac{1}{8} \times 3S Solve for SS: S=12×83=32cm2S = \frac{12 \times 8}{3} = 32 \, \text{cm}^2

  6. Total area of the whole figure: Since the whole figure consists of 3 squares: Total Area=3S=3×32=96cm2\text{Total Area} = 3S = 3 \times 32 = 96 \, \text{cm}^2


(b) Express the total areas of PP and QQ as a fraction of one square.

  1. From the above calculation, the area of one square is: S=32cm2S = 32 \, \text{cm}^2
  2. The combined area of PP and QQ is: P+Q=12cm2P + Q = 12 \, \text{cm}^2
  3. Express as a fraction of one square: P+QS=1232=38\frac{P + Q}{S} = \frac{12}{32} = \frac{3}{8}

Final answers:

(a) The total area of the whole figure is 96cm296 \, \text{cm}^2.
(b) The total areas of PP and QQ as a fraction of one square is 38\frac{3}{8}.


Let me know if you want detailed steps or additional explanations!

5 Related Questions:

  1. How is the overlapping area between PP and QQ calculated if it is explicitly provided?
  2. Can you find the side length of each square given its area?
  3. What is the area of the unshaded region of the entire figure?
  4. How would the solution change if the shaded fraction were 16\frac{1}{6} instead of 18\frac{1}{8}?
  5. What is the relationship between the number of squares and the fraction of the shaded area?

1 Tip:

Always write down all known areas and relationships in geometric problems before solving equations—this reduces the chance of confusion!

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Math Problem Analysis

Mathematical Concepts

Geometry
Fractions
Area Calculation

Formulas

Total Area = Sum of individual parts
Fractional Area = (Fraction) × (Total Area)
Area of Overlapping Regions = Sum of overlapping rectangles

Theorems

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Suitable Grade Level

Grades 7-8