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The diagram describes the behavior of light reflecting off a surface, following the law of reflection, which states that the angle of incidence \( i \) is equal to the angle of reflection \( r \). The task asks to find the values of the angles \( x \) and \( y \).

### Analysis:
1. The angle of incidence \( i \) is given as \( 60^\circ \). 
2. By the law of reflection, the angle of reflection \( r \) is also \( 60^\circ \).
3. The angles \( x \) and \( y \) are supplementary to the angles of incidence and reflection, respectively, because they form a linear pair with those angles.

### Calculations:
- Since \( x \) is supplementary to \( i \), we can find it using:
  \[
  x = 180^\circ - i = 180^\circ - 60^\circ = 120^\circ
  \]
- Similarly, \( y \) is supplementary to \( r \):
  \[
  y = 180^\circ - r = 180^\circ - 60^\circ = 120^\circ
  \]

Thus, the values of the angles are:
- \( x = 120^\circ \)
- \( y = 120^\circ \)

Would you like any further details on this solution or have any questions?

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Here are 5 related questions:
1. How does the law of reflection apply to curved surfaces?
2. What would happen to the angles if the incident angle was increased?
3. Can reflection occur at any angle? What are the limits, if any?
4. What is the difference between specular and diffuse reflection?
5. How does Snell's law relate to the law of reflection?

**Tip:** Always remember that in reflection, the angle is measured with respect to the normal (a perpendicular line) to the surface, not the surface itself.

When light is reflected, the angle of incidence (i) equals the angle of reflection (r). Find the values of the angles x and y.

Learn how to find the angles of incidence and reflection in this geometry problem. Understand how the law of reflection applies, using supplementary angles to calculate the values of x and y. Suitable for students in Grades 6-8.

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