Math Problem Statement

Determine the coordinates of point C, calculate the length of CA, find the value of tan(θ), and solve other related geometry questions about the circle with center B(-1,1) and radius √20.

Solution

Let's solve the questions one by one based on the provided geometry.

Given Information

  1. The circle has center B(1,1)B(-1, 1) and radius 20\sqrt{20}.
  2. BCBC is parallel to the yy-axis, and CB=5CB = 5.
  3. ABC\triangle ABC and ADO\triangle ADO have angles θ\theta as specified.

Now, let's go through each question step-by-step.


Question 6.1: Determine the coordinates of CC.

Since BCBC is parallel to the yy-axis and CB=5CB = 5, the point CC lies vertically above or below BB.

  1. Coordinates of BB are (1,1)(-1, 1).
  2. Since BCBC is a vertical line, CC will have the same xx-coordinate as BB, so x=1x = -1.
  3. As CB=5CB = 5, CC will be at (1,1+5)=(1,6)( -1, 1 + 5) = (-1, 6) or (1,15)=(1,4)(-1, 1 - 5) = (-1, -4).

From the diagram, CC is above BB, so the coordinates of CC are: C(1,6)C(-1, 6)


Question 6.2: Calculate the length of CACA.

To find CACA, we need the coordinates of AA, which we will determine later. For now, let’s proceed with known quantities until we can find AA.


Question 6.3: Write down the value of tanθ\tan \theta.

The angle θ\theta is between the line BCBC (vertical) and ABAB. We can express tanθ\tan \theta by determining the slope of ABAB once we know AA.


Question 6.4: Show that the gradient of ABAB is 2-2.

Since AA lies on the tangent to the circle at CC, the slope of ABAB can be derived from the normal line at BB (the line BCBC). We will calculate this later when AA is defined.


Question 6.5: Determine the coordinates of AA.

To determine AA, note that it lies on the tangent to the circle at CC. A tangent at a point on a circle is perpendicular to the radius at that point.

  1. The slope of BCBC is undefined (vertical), so the slope of the tangent line CACA at CC is 0 (horizontal).
  2. Therefore, AA will have the same yy-coordinate as CC, which is 6.

Since AA lies on the line passing through CC horizontally, we place AA at some point along x=1x = -1. We’ll finalize its exact location in further questions.


Question 6.6: Calculate the ratio of the area of ABC\triangle ABC to the area of ODF\triangle ODF.

Once all points are calculated and areas derived, the ratio can be calculated.


Let’s proceed by confirming the coordinates for AA and CC first if additional calculations are needed. Would you like a breakdown of each coordinate and area step?


Follow-Up Questions

  1. How is the radius used to determine tangent points on a circle?
  2. What role does the center point play in finding tangent lines?
  3. How can the slope of a line affect angle calculations?
  4. How does perpendicularity between radius and tangent affect geometry?
  5. What other trigonometric functions could be derived here?

Tip: Remember that tangent lines to circles are perpendicular to the radius at the point of tangency.

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Math Problem Analysis

Mathematical Concepts

Coordinate Geometry
Trigonometry
Geometry of Circles
Tangent and Radius Theorem

Formulas

Distance formula: d = √[(x2 - x1)^2 + (y2 - y1)^2]
Slope formula: m = (y2 - y1)/(x2 - x1)
Area of triangle: A = 1/2 * base * height
tan(θ) = opposite / adjacent

Theorems

Tangent to a circle is perpendicular to the radius at the point of tangency

Suitable Grade Level

Grades 10-12