Math Problem Statement

Prove the formula for the sum of a geometric series: a + ar + ar^2 + ... + ar^(n-1) = a(1 - r^n) / (1 - r) using mathematical induction. Verify it for n = 1.

Solution

This image appears to be part of a proof or derivation for the sum of a geometric series. Let’s break it down:

The Statement

The geometric series sum formula is being tested or proven for the series: Sn=a+ar+ar2++arn1,S_n = a + ar + ar^2 + \dots + ar^{n-1}, and its closed form: Sn=a1rn1r,r1.S_n = a \frac{1 - r^n}{1 - r}, \quad r \neq 1.

Step in the Proof

  • For n=1n = 1:
    • Left-Hand Side (LHS): S1=a,S_1 = a, since only the first term is included.
    • Right-Hand Side (RHS): Substitute n=1n = 1 into the formula: S1=a1r11r.S_1 = a \frac{1 - r^1}{1 - r}. Simplify the numerator: S1=a1r1r=a,S_1 = a \frac{1 - r}{1 - r} = a, which matches the LHS.

This confirms the formula works for n=1n = 1. The next steps would likely involve proving the formula for n>1n > 1, possibly using mathematical induction.


Would you like to continue with the full proof using induction, or clarify any steps?


Related Questions

  1. How does the formula for a finite geometric series work for r>1r > 1?
  2. What happens when r=1r = 1 in the series formula?
  3. Can we derive this formula from first principles without induction?
  4. How is the infinite geometric series related to this formula?
  5. What real-world problems can be modeled with a geometric series?

Tip

When solving series problems, always verify boundary cases like n=1n = 1 or r=1r = 1 for correctness!

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Math Problem Analysis

Mathematical Concepts

Algebra
Geometric Progressions
Mathematical Induction

Formulas

Sum of finite geometric series: S_n = a(1 - r^n)/(1 - r), r ≠ 1

Theorems

Mathematical Induction

Suitable Grade Level

Grades 11-12