Math Problem Statement

Write a recursive formula and an explicit formula for each geometric sequence: 1. 9, 18, 36, 72, ... 2. 540, 180, 60, 20, ...

Solution

To solve this, we need both recursive and explicit formulas for each given geometric sequence. Let's tackle them one at a time.


Problem 4: Sequence: 9, 18, 36, 72, ...

  1. Identify the common ratio:
    The common ratio rr is obtained by dividing any term by the previous one:
    r=next termprevious term=189=2.r = \frac{\text{next term}}{\text{previous term}} = \frac{18}{9} = 2. So the sequence multiplies by 22 at each step.

  2. Recursive formula:
    The recursive formula defines each term based on the previous one:
    an=an1r,where a1=9 and r=2.a_n = a_{n-1} \cdot r, \quad \text{where } a_1 = 9 \text{ and } r = 2. Therefore:
    an=an12with a1=9.a_n = a_{n-1} \cdot 2 \quad \text{with } a_1 = 9.

  3. Explicit formula:
    The explicit formula for a geometric sequence is:
    an=a1rn1.a_n = a_1 \cdot r^{n-1}. Substituting a1=9a_1 = 9 and r=2r = 2:
    an=92n1.a_n = 9 \cdot 2^{n-1}.


Problem 5: Sequence: 540, 180, 60, 20, ...

  1. Identify the common ratio:
    The common ratio rr is obtained by dividing any term by the previous one:
    r=next termprevious term=180540=13.r = \frac{\text{next term}}{\text{previous term}} = \frac{180}{540} = \frac{1}{3}. So the sequence multiplies by 13\frac{1}{3} at each step.

  2. Recursive formula:
    The recursive formula defines each term based on the previous one:
    an=an1r,where a1=540 and r=13.a_n = a_{n-1} \cdot r, \quad \text{where } a_1 = 540 \text{ and } r = \frac{1}{3}. Therefore:
    an=an113with a1=540.a_n = a_{n-1} \cdot \frac{1}{3} \quad \text{with } a_1 = 540.

  3. Explicit formula:
    The explicit formula for a geometric sequence is:
    an=a1rn1.a_n = a_1 \cdot r^{n-1}. Substituting a1=540a_1 = 540 and r=13r = \frac{1}{3}:
    an=540(13)n1.a_n = 540 \cdot \left(\frac{1}{3}\right)^{n-1}.


Final Answers:

For sequence 9,18,36,72,9, 18, 36, 72, \dots:

  • Recursive: an=an12,a1=9a_n = a_{n-1} \cdot 2, \, a_1 = 9
  • Explicit: an=92n1a_n = 9 \cdot 2^{n-1}

For sequence 540,180,60,20,540, 180, 60, 20, \dots:

  • Recursive: an=an113,a1=540a_n = a_{n-1} \cdot \frac{1}{3}, \, a_1 = 540
  • Explicit: an=540(13)n1a_n = 540 \cdot \left(\frac{1}{3}\right)^{n-1}

Do you need any further explanation or examples? Let me know!

Related Questions:

  1. What is the general form of a geometric sequence's explicit formula?
  2. How do you determine the common ratio in a geometric sequence?
  3. How do recursive and explicit formulas differ in application?
  4. Can a geometric sequence have a negative common ratio? Give an example.
  5. How do you solve for a specific term in a geometric sequence using its explicit formula?

Tip:

To quickly check if a sequence is geometric, divide consecutive terms to ensure the ratio is constant.

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Math Problem Analysis

Mathematical Concepts

Geometric Sequences
Recursive Formulas
Explicit Formulas
Common Ratio

Formulas

Recursive formula: a_n = a_(n-1) * r
Explicit formula: a_n = a_1 * r^(n-1)

Theorems

Geometric Sequence Formula

Suitable Grade Level

Grades 8-10