Math Problem Statement

1/3 and 64/1 find the 1 geometric mean

Solution

To find the geometric mean between two numbers, we use the following formula:

Geometric mean=a×b\text{Geometric mean} = \sqrt{a \times b}

where aa and bb are the two numbers.

In this case, a=13a = \frac{1}{3} and b=641b = \frac{64}{1}.

Now, calculate the geometric mean:

Geometric mean=13×64=643\text{Geometric mean} = \sqrt{\frac{1}{3} \times 64} = \sqrt{\frac{64}{3}}

Thus, the geometric mean is:

Geometric mean=6434.6188\text{Geometric mean} = \sqrt{\frac{64}{3}} \approx 4.6188

Let me know if you want more details or have any questions.

Here are some related questions for practice:

  1. What is the geometric mean of 5 and 20?
  2. Find the geometric mean of 25\frac{2}{5} and 252\frac{25}{2}.
  3. Calculate the geometric mean of 9 and 16.
  4. How is the geometric mean different from the arithmetic mean?
  5. What is the geometric mean of 10 and 0.1?

Tip: The geometric mean is most useful when comparing quantities that multiply together, such as growth rates.

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Math Problem Analysis

Mathematical Concepts

Algebra
Geometric Mean
Square Roots

Formulas

Geometric mean formula: sqrt(a * b)

Theorems

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Suitable Grade Level

Grades 7-9