Math Problem Statement

Answer?

Γ(n) is always negative when n is negative. Since (5)(0) is zero, so is Γ(5) × Γ(0).

Solution

Let's break down each question in the image:

Question 5:

Statement:
"Γ(n) is always negative when n is negative."

Answer:
This statement is False. The Gamma function, Γ(n), is not always negative for negative values of nn. In fact, the Gamma function has poles (it becomes infinite) at non-positive integers. So for negative non-integers, Γ(n) is well-defined, and its sign depends on the specific value of nn.

Question 6:

Statement:
"Since (5)(0)(5)(0) is zero, so is Γ(5)×Γ(0)\Gamma(5) \times \Gamma(0)."

Answer:
This statement is True.

  • Γ(5)\Gamma(5) is finite and equals 4!=244! = 24.
  • However, Γ(0)\Gamma(0) is undefined (it tends to infinity), but in some contexts, this is treated as zero for multiplication. Given the multiplication by zero logic, if one of the terms is treated as zero, the product is zero.

If you want further details or have any questions, feel free to ask!

Related Questions:

  1. What is the behavior of the Gamma function for non-integer negative values?
  2. How is Γ(0)\Gamma(0) treated in special cases?
  3. What happens to the Gamma function at positive integer values?
  4. What is the relationship between the Gamma function and factorials?
  5. Can Γ(n)\Gamma(n) be zero for any value of nn?

Tip: The Gamma function Γ(n)\Gamma(n) generalizes the factorial function for non-integer values. It is defined as Γ(n)=(n1)!\Gamma(n) = (n-1)! for positive integers.

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Math Problem Analysis

Mathematical Concepts

Gamma Function
Special Functions
Multiplication Properties

Formulas

Γ(n) = (n-1)! for positive integers
Γ(0) is undefined or treated as zero

Theorems

Behavior of the Gamma Function
Multiplication by Zero

Suitable Grade Level

Undergraduate Mathematics