Math Problem Statement

if f(x) + f(x-1) = x^2 and f(20) = 90 then find f(90)

Solution

We are given the functional equation:

f(x)+f(x1)=x2f(x) + f(x-1) = x^2

and the additional condition f(20)=90f(20) = 90. We are tasked with finding f(90)f(90).

Step 1: Use the given functional equation

The functional equation can be rewritten as:

f(x)=x2f(x1)f(x) = x^2 - f(x-1)

This allows us to express each value of f(x)f(x) in terms of the previous function value, which suggests a recursive approach.

Step 2: Apply known values

We are given f(20)=90f(20) = 90. Let's start calculating values backward using the recursion:

For f(19)f(19):

f(20)+f(19)=202=400f(20) + f(19) = 20^2 = 400 90+f(19)=40090 + f(19) = 400 f(19)=40090=310f(19) = 400 - 90 = 310

For f(18)f(18):

f(19)+f(18)=192=361f(19) + f(18) = 19^2 = 361 310+f(18)=361310 + f(18) = 361 f(18)=361310=51f(18) = 361 - 310 = 51

For f(17)f(17):

f(18)+f(17)=182=324f(18) + f(17) = 18^2 = 324 51+f(17)=32451 + f(17) = 324 f(17)=32451=273f(17) = 324 - 51 = 273

Step 3: Continue backward

At this point, we notice that continuing backward step by step would become too cumbersome. However, the recurrence relation f(x)=x2f(x1)f(x) = x^2 - f(x-1) offers a key insight into the structure of the function. We could calculate further terms if needed but would consider a direct or alternate pattern-based approach for values like f(90)f(90).

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Math Problem Analysis

Mathematical Concepts

Algebra
Functional Equations
Recursion

Formulas

f(x) + f(x-1) = x^2
f(x) = x^2 - f(x-1)

Theorems

Recursive Relations

Suitable Grade Level

Grades 9-12