Math Problem Statement

Find f plus g​, f minus g​, ​fg, and StartFraction f Over g EndFraction . Determine the domain for each function. f left parenthesis x right parenthesis equals StartRoot x EndRoot​; g left parenthesis x right parenthesis equals x minus 13 Write domain in interval notation

Solution

We are given two functions:

f(x)=xf(x) = \sqrt{x} g(x)=x13g(x) = x - 13

We are asked to find the following operations and their domains:

1. (f+g)(x)(f + g)(x)

This is the sum of the functions f(x)f(x) and g(x)g(x):

(f+g)(x)=f(x)+g(x)=x+(x13)(f + g)(x) = f(x) + g(x) = \sqrt{x} + (x - 13)

Domain of (f+g)(x)(f + g)(x):

  • The function f(x)=xf(x) = \sqrt{x} is defined for x0x \geq 0, because square roots of negative numbers are not real.
  • The function g(x)=x13g(x) = x - 13 is defined for all real values of xx, since it is a polynomial.

Thus, the domain of (f+g)(x)(f + g)(x) is determined by the domain of f(x)f(x), so:

Domain of (f+g)(x)=[0,)\text{Domain of } (f + g)(x) = [0, \infty)

2. (fg)(x)(f - g)(x)

This is the difference of the functions f(x)f(x) and g(x)g(x):

(fg)(x)=f(x)g(x)=x(x13)(f - g)(x) = f(x) - g(x) = \sqrt{x} - (x - 13)

Domain of (fg)(x)(f - g)(x):

  • Again, f(x)=xf(x) = \sqrt{x} requires x0x \geq 0.
  • g(x)=x13g(x) = x - 13 is defined for all real xx.

Thus, the domain of (fg)(x)(f - g)(x) is also:

Domain of (fg)(x)=[0,)\text{Domain of } (f - g)(x) = [0, \infty)

3. (fg)(x)(f \cdot g)(x)

This is the product of the functions f(x)f(x) and g(x)g(x):

(fg)(x)=f(x)g(x)=x(x13)(f \cdot g)(x) = f(x) \cdot g(x) = \sqrt{x} \cdot (x - 13)

Domain of (fg)(x)(f \cdot g)(x):

  • f(x)=xf(x) = \sqrt{x} requires x0x \geq 0.
  • g(x)=x13g(x) = x - 13 is defined for all xx.

Thus, the domain of (fg)(x)(f \cdot g)(x) is also:

Domain of (fg)(x)=[0,)\text{Domain of } (f \cdot g)(x) = [0, \infty)

4. fg(x)\frac{f}{g}(x)

This is the quotient of the functions f(x)f(x) and g(x)g(x):

fg(x)=xx13\frac{f}{g}(x) = \frac{\sqrt{x}}{x - 13}

Domain of fg(x)\frac{f}{g}(x):

  • f(x)=xf(x) = \sqrt{x} requires x0x \geq 0.
  • g(x)=x13g(x) = x - 13 is defined for all xx, but we cannot divide by zero, so we must exclude x=13x = 13.

Thus, the domain of fg(x)\frac{f}{g}(x) is:

Domain of fg(x)=[0,13)(13,)\text{Domain of } \frac{f}{g}(x) = [0, 13) \cup (13, \infty)

Summary

  • (f+g)(x)=x+(x13)(f + g)(x) = \sqrt{x} + (x - 13) has domain [0,)[0, \infty)
  • (fg)(x)=x(x13)(f - g)(x) = \sqrt{x} - (x - 13) has domain [0,)[0, \infty)
  • (fg)(x)=x(x13)(f \cdot g)(x) = \sqrt{x} \cdot (x - 13) has domain [0,)[0, \infty)
  • fg(x)=xx13\frac{f}{g}(x) = \frac{\sqrt{x}}{x - 13} has domain [0,13)(13,)[0, 13) \cup (13, \infty)

Would you like any further clarification or additional questions on these functions?

Here are some related questions to explore:

  1. How would you determine the domain of a composite function, such as (fg)(x)(f \circ g)(x)?
  2. What is the difference in domain restrictions between rational and irrational functions?
  3. How do you handle square roots of negative numbers in real-valued functions?
  4. Can you find the range of the function f(x)=xf(x) = \sqrt{x}?
  5. How would you solve a real-world problem where square roots and linear functions are combined?

Tip: When working with square roots, always remember that the domain is restricted to values that make the expression under the square root non-negative!

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Math Problem Analysis

Mathematical Concepts

Functions
Domain and Range
Square Roots
Polynomial Functions
Rational Functions

Formulas

(f + g)(x) = f(x) + g(x)
(f - g)(x) = f(x) - g(x)
(f * g)(x) = f(x) * g(x)
(f / g)(x) = f(x) / g(x)

Theorems

The domain of a square root function is x ≥ 0
The domain of a polynomial function is all real numbers
The domain of a rational function excludes values that make the denominator zero

Suitable Grade Level

Grades 9-12