Math Problem Statement

Create a function f(x,y) that have at least 1 minimum, 1 maximum and 1 saddle point. **Use the Hessian determinant to confirm your answer. You can also try to sketch its graph using 3D graphing tool.

Solution

The 3D plot of the function f(x,y)=x33x+y2f(x, y) = x^3 - 3x + y^2 visually confirms the nature of the critical points:

  • The point (1,0)(1, 0) corresponds to a local minimum.
  • The point (1,0)(-1, 0) corresponds to a saddle point.

This function also exhibits behavior consistent with these classifications based on the Hessian determinant analysis.

Follow-Up Questions:

  1. How does the behavior of the Hessian determinant affect the classification of critical points?
  2. What would happen if you modified the function to f(x,y)=x44x2+y2f(x, y) = x^4 - 4x^2 + y^2?
  3. Can a function have multiple saddle points and still have only one maximum or minimum?
  4. How does the shape of the graph change if you modify the coefficients of the function?
  5. What is the effect of adding a constant term to f(x,y)f(x, y) on its critical points?

Tip: Understanding the second derivative test helps classify critical points quickly and accurately.

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Math Problem Analysis

Mathematical Concepts

Multivariable Calculus
Critical Points
Hessian Determinant

Formulas

Hessian determinant for critical point classification

Theorems

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Suitable Grade Level

Advanced Mathematics