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Let's solve the problem step by step.

### Problem Summary:
- Shane jumped \( \frac{7}{9} \) yards.
- Jorge jumped \( \frac{3}{4} \) yards.

We are tasked to:
1. Find the **LCD** (Lowest Common Denominator) of these fractions.
2. Determine who jumped higher.

### Step 1: Find the LCD
To compare these fractions, we need to find the **Least Common Denominator** (LCD) between \( \frac{7}{9} \) and \( \frac{3}{4} \).

- The denominators are 9 and 4.
- The **LCD** of 9 and 4 is the least common multiple (LCM) of these numbers.

LCM of 9 and 4:
- \( 9 = 3^2 \)
- \( 4 = 2^2 \)

The LCM is \( 2^2 \times 3^2 = 4 \times 9 = 36 \).

So, the **LCD** is **36**.

### Step 2: Convert to Equivalent Fractions
Now, we convert both fractions to have the denominator 36.

- \( \frac{7}{9} \times \frac{4}{4} = \frac{28}{36} \)
- \( \frac{3}{4} \times \frac{9}{9} = \frac{27}{36} \)

### Step 3: Compare the Fractions
- Shane jumped \( \frac{28}{36} \) yards.
- Jorge jumped \( \frac{27}{36} \) yards.

Since \( \frac{28}{36} > \frac{27}{36} \), **Shane** jumped higher.

### Final Answers:
- **LCD** = 36
- **Who jumped higher?** Shane

Would you like more details or further clarification?

### 5 Related Questions:
1. How do you find the Least Common Denominator (LCD) for any two fractions?
2. What is the difference between LCD and LCM?
3. How do you convert fractions to equivalent fractions with a common denominator?
4. How can you compare fractions with different denominators?
5. How do you determine which fraction is greater after converting to a common denominator?

### Tip:
When comparing fractions, always ensure to convert them to a common denominator to make the comparison easier.

Shane high jumped 7/9 yd., and Jorge jumped 3/4 yd. Who jumped the highest? Find the LCD of the two fractions. Change to equivalent fractions. Who jumped higher?

Learn how to solve a fraction comparison problem where Shane jumped 7/9 yd and Jorge jumped 3/4 yd. This problem focuses on finding the Least Common Denominator (LCD) of 9 and 4, converting fractions to equivalent forms, and determining who jumped higher. Suitable for students in Grades 6-8.

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