Math Problem Statement

Find the Fourier series expansion of the periodic function f(x), defined as -π < x < π and f(x + 2π) = f(x).

Solution

The problem is asking for the Fourier series expansion of a periodic function f(x)f(x), defined over the interval π<x<π-\pi < x < \pi, with the condition that f(x+2π)=f(x)f(x+2\pi) = f(x), meaning the function is periodic with period 2π2\pi.

General Fourier Series Formulation

The Fourier series of a periodic function f(x)f(x) with period 2π2\pi is given by: f(x)=a0+n=1[ancos(nx)+bnsin(nx)]f(x) = a_0 + \sum_{n=1}^\infty \left[ a_n \cos(nx) + b_n \sin(nx) \right] where the coefficients are defined as:

  1. a0=12πππf(x)dxa_0 = \frac{1}{2\pi} \int_{-\pi}^\pi f(x) \, dx
  2. an=1πππf(x)cos(nx)dxa_n = \frac{1}{\pi} \int_{-\pi}^\pi f(x) \cos(nx) \, dx
  3. bn=1πππf(x)sin(nx)dxb_n = \frac{1}{\pi} \int_{-\pi}^\pi f(x) \sin(nx) \, dx

Steps to Solve

  1. Compute a0a_0:
    • a0a_0 is the average value of f(x)f(x) over one period.
  2. Compute ana_n:
    • These coefficients measure the cosine contributions to f(x)f(x).
  3. Compute bnb_n:
    • These coefficients measure the sine contributions to f(x)f(x).

Required Input

For a complete solution, the function f(x)f(x) must be explicitly provided (e.g., f(x)=xf(x) = x, f(x)=xf(x) = |x|, etc.).

Would you like to proceed with a specific function for f(x)f(x), or should I provide a general explanation? Let me know!

5 Questions for You:

  1. Do you have a specific definition for f(x)f(x) within πxπ-\pi \leq x \leq \pi?
  2. Should I demonstrate the solution using a common example, like f(x)=xf(x) = x?
  3. Are you familiar with the integration techniques needed for calculating the coefficients?
  4. Would you like a step-by-step explanation for each coefficient (a0,an,bna_0, a_n, b_n)?
  5. Should I include a graph of the Fourier series approximation?

Tip:

Always visualize the original function and its Fourier series approximation to better understand how the series converges to the function over its domain.

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Math Problem Analysis

Mathematical Concepts

Fourier Series
Periodic Functions
Integration

Formulas

f(x) = a_0 + Σ (a_n * cos(nx) + b_n * sin(nx))
a_0 = (1 / 2π) ∫_{-π}^π f(x) dx
a_n = (1 / π) ∫_{-π}^π f(x) cos(nx) dx
b_n = (1 / π) ∫_{-π}^π f(x) sin(nx) dx

Theorems

Fourier Series Expansion Theorem

Suitable Grade Level

Undergraduate Mathematics or Advanced High School