Math Problem Statement

Write down formulas for the perimeter (P mm) and area (A cm²) of the given composite shapes.

Solution

Let's analyze the image step-by-step to solve the given questions.


Question 8: Write down a formula for the perimeter PP mm

The shapes provided consist of a semi-circle attached to a rectangle and a straight edge (triangle-like structure). For each case:

General Formula for Perimeter

The perimeter consists of:

  1. The curved part of the semi-circle
    • Length of a semi-circle: πr\pi r, where rr is the radius.
  2. The two straight edges of the rectangle and triangle-like part.
  3. The base of the shape (width of the rectangle).

The total perimeter PP is given by: P=πr+straight edges+baseP = \pi r + \text{straight edges} + \text{base}


Part (a)

  • Given: Radius of semi-circle r=20mmr = 20 \, \text{mm}, and width of the base = 50mm50 \, \text{mm}.
  • Formula: P=πr+2×straight edge+baseP = \pi r + 2 \times \text{straight edge} + \text{base} Substituting r=20r = 20: P=π(20)+2(40)+50P = \pi(20) + 2(40) + 50

Part (b)

  • Given: Radius of semi-circle r=40mmr = 40 \, \text{mm}, base = amma \, \text{mm}.
  • Formula: P=πr+2×straight edge+aP = \pi r + 2 \times \text{straight edge} + a Substituting r=40r = 40: P=π(40)+2×straight edge+aP = \pi(40) + 2 \times \text{straight edge} + a

Part (c) and (d)

  • These parts generalize the same pattern using:
    • Radius rr = cmmc \, \text{mm} (part d)
    • Base = amma \, \text{mm}

The general formula: P=πr+2×straight edge+aP = \pi r + 2 \times \text{straight edge} + a


Question 9: Write down a formula for the area Acm2A \, \text{cm}^2

The shapes provided are H-shaped, composed of three rectangles. To find the total area AA, sum the areas of each rectangle.

General Formula

For any H-shaped structure:

  1. The total area is given by subtracting the cut-out rectangle areas from the large rectangle: A=Area of large rectangle2×Area of cut-out rectanglesA = \text{Area of large rectangle} - 2 \times \text{Area of cut-out rectangles}

Part (a)

  • Large rectangle: Width = 3cm3 \, \text{cm}, height = 8cm8 \, \text{cm}.
    Area = 3×8=24cm23 \times 8 = 24 \, \text{cm}^2
  • Cut-out rectangles: Each cut-out has height 3cm3 \, \text{cm}, width 2cm2 \, \text{cm}.
    Area of one cut-out = 2×3=6cm22 \times 3 = 6 \, \text{cm}^2.

A=242(6)=2412=12cm2A = 24 - 2(6) = 24 - 12 = 12 \, \text{cm}^2


Part (b) and (c)

  • General Formula:
    Let the large rectangle's dimensions be mcmm \, \text{cm} wide and 8cm8 \, \text{cm} high, with cut-out areas.

A=Area of large rectangle2×Area of cut-out rectanglesA = \text{Area of large rectangle} - 2 \times \text{Area of cut-out rectangles}

For part b and c, replace mm and nn into this formula.


Do you want me to explain any part further or provide exact solutions for all steps?


Related Questions

  1. How do you calculate the perimeter of a composite shape with circles and straight lines?
  2. What is the relationship between area and perimeter for a rectangle?
  3. How do you generalize the formula for shapes with multiple components?
  4. What is the perimeter of a semi-circular arc combined with a rectangle?
  5. How can you simplify formulas for composite shapes?

Tip: Always break down complex shapes into simpler components (e.g., rectangles, triangles, circles) to calculate area or perimeter easily.

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Math Problem Analysis

Mathematical Concepts

Geometry
Composite Shapes
Perimeter
Area
Semi-Circle
Rectangles

Formulas

Perimeter of a semi-circle = πr
Perimeter of composite shape = curved part + straight edges + base
Area of rectangle = width × height
Area of composite shapes = Area of larger rectangle - 2 × Area of cut-out rectangles

Theorems

Relationship between the perimeter of semi-circular arcs and their radii.
Area subtraction for composite shapes.

Suitable Grade Level

Grade 6-8