Math Problem Statement

Form a polynomial f(x) with real coefficients having the given degree and zeros

Solution

To form a polynomial f(x)f(x) with real coefficients given its degree and zeros, we need to follow these steps:

Steps:

  1. Identify the degree and zeros: From the problem, the degree of the polynomial is determined by the number of zeros. If the zeros are complex, remember that non-real zeros of polynomials with real coefficients must come in conjugate pairs.

  2. Write factors based on zeros:

    • If aa is a real zero, include a factor (xa)(x - a).
    • If a+bia + bi is a complex zero, include a factor (x(a+bi))(x(abi))(x - (a + bi))(x - (a - bi)), which simplifies to (x22ax+a2+b2)(x^2 - 2ax + a^2 + b^2).
  3. Multiply the factors: Once all the factors are identified, multiply them together to form the polynomial.

  4. Simplify: Combine like terms to write the polynomial in standard form.

Example Problem:

Suppose the polynomial has degree 4 and the given zeros are:

  • 22 (real zero),
  • 3-3 (real zero),
  • 1+2i1 + 2i (complex zero, which implies that 12i1 - 2i is also a zero).

Forming the Polynomial:

  1. Write the factors:

    • For 22, the factor is (x2)(x - 2).
    • For 3-3, the factor is (x+3)(x + 3).
    • For 1+2i1 + 2i and 12i1 - 2i, use (x(1+2i))(x(12i))(x - (1 + 2i))(x - (1 - 2i)), which simplifies to (x22x+5)(x^2 - 2x + 5) (from the identity (x(a+bi))(x(abi))=x22ax+a2+b2(x - (a + bi))(x - (a - bi)) = x^2 - 2ax + a^2 + b^2).
  2. Multiply the factors: f(x)=(x2)(x+3)(x22x+5)f(x) = (x - 2)(x + 3)(x^2 - 2x + 5)

  3. Expand: First, multiply (x2)(x - 2) and (x+3)(x + 3): (x2)(x+3)=x2+3x2x6=x2+x6(x - 2)(x + 3) = x^2 + 3x - 2x - 6 = x^2 + x - 6

    Now, multiply (x2+x6)(x^2 + x - 6) by (x22x+5)(x^2 - 2x + 5): f(x)=(x2+x6)(x22x+5)f(x) = (x^2 + x - 6)(x^2 - 2x + 5) Expand this: f(x)=x42x3+5x2+x32x2+5x6x2+12x30f(x) = x^4 - 2x^3 + 5x^2 + x^3 - 2x^2 + 5x - 6x^2 + 12x - 30 Combine like terms: f(x)=x4x33x2+17x30f(x) = x^4 - x^3 - 3x^2 + 17x - 30

So, the polynomial is: f(x)=x4x33x2+17x30f(x) = x^4 - x^3 - 3x^2 + 17x - 30

Let me know if you'd like a breakdown of any steps!


Related Questions:

  1. What happens if a zero has multiplicity greater than 1?
  2. How do we handle polynomials with more than two complex roots?
  3. Can you find a polynomial where all roots are complex numbers?
  4. How does the Fundamental Theorem of Algebra help in finding polynomial roots?
  5. What is the relationship between the degree of a polynomial and the number of turning points?

Tip: When multiplying complex conjugates, always simplify using (x22ax+a2+b2)(x^2 - 2ax + a^2 + b^2) to avoid handling imaginary terms directly.

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Math Problem Analysis

Mathematical Concepts

Algebra
Polynomials
Complex Numbers
Roots of Polynomials

Formulas

Factorization: (x - a) for real zeros
(x - (a + bi))(x - (a - bi)) = x^2 - 2ax + a^2 + b^2 for complex conjugates

Theorems

Fundamental Theorem of Algebra

Suitable Grade Level

Grades 10-12