Math Problem Statement

Form a polynomial function in its standard form from the given real zeros and degree. Assume that the stretch-compression factor is 1. The problems are: a) Zeros: -5, -2, 4; Degree: 3, b) Zeros: 7, multiplicity 1; -4, multiplicity 3; -3, multiplicity 1; Degree: 5, c) Zeros: 3, multiplicity 2; 0, multiplicity 2; -1, multiplicity 1; Degree: 5

Solution

Let's work through each part of the problem.

We are asked to form polynomial functions based on the given zeros, their multiplicities, and the degrees. We'll assume the stretch-compression factor is 1, meaning the leading coefficient is 1.

a) Zeros: -5, -2, 4; Degree: 3

  • The polynomial will have factors of (x+5)(x + 5), (x+2)(x + 2), and (x4)(x - 4) since the zeros are 5-5, 2-2, and 44.
  • The polynomial is: P(x)=(x+5)(x+2)(x4)P(x) = (x + 5)(x + 2)(x - 4) We expand this: P(x)=(x+5)(x+2)(x4)P(x) = (x + 5)(x + 2)(x - 4) First, expand (x+5)(x+2)(x + 5)(x + 2): (x+5)(x+2)=x2+7x+10(x + 5)(x + 2) = x^2 + 7x + 10 Now multiply by (x4)(x - 4): P(x)=(x2+7x+10)(x4)P(x) = (x^2 + 7x + 10)(x - 4) P(x)=x34x2+7x228x+10x40P(x) = x^3 - 4x^2 + 7x^2 - 28x + 10x - 40 P(x)=x3+3x218x40P(x) = x^3 + 3x^2 - 18x - 40

b) Zeros: 7, multiplicity 1; -4, multiplicity 3; -3, multiplicity 1; Degree: 5

  • The factors are (x7)(x - 7), (x+4)3(x + 4)^3, and (x+3)(x + 3).
  • The polynomial is: P(x)=(x7)(x+4)3(x+3)P(x) = (x - 7)(x + 4)^3(x + 3) We expand step by step. First, expand (x+4)3(x + 4)^3: (x+4)3=(x+4)(x+4)(x+4)(x + 4)^3 = (x + 4)(x + 4)(x + 4) Expanding the first two factors: (x+4)(x+4)=x2+8x+16(x + 4)(x + 4) = x^2 + 8x + 16 Now, multiply by (x+4)(x + 4): (x2+8x+16)(x+4)=x3+12x2+48x+64(x^2 + 8x + 16)(x + 4) = x^3 + 12x^2 + 48x + 64 Now multiply by (x7)(x - 7): (x7)(x3+12x2+48x+64)(x - 7)(x^3 + 12x^2 + 48x + 64) P(x)=x4+5x336x2288x448P(x) = x^4 + 5x^3 - 36x^2 - 288x - 448 Finally, multiply by (x+3)(x + 3): (x4+5x336x2288x448)(x+3)(x^4 + 5x^3 - 36x^2 - 288x - 448)(x + 3) Expanding: P(x)=x5+8x421x3396x21312x1344P(x) = x^5 + 8x^4 - 21x^3 - 396x^2 - 1312x - 1344

c) Zeros: 3, multiplicity 2; 0, multiplicity 2; -1, multiplicity 1; Degree: 5

  • The factors are (x3)2(x - 3)^2, x2x^2, and (x+1)(x + 1).
  • The polynomial is: P(x)=(x3)2x2(x+1)P(x) = (x - 3)^2x^2(x + 1) First, expand (x3)2(x - 3)^2: (x3)2=x26x+9(x - 3)^2 = x^2 - 6x + 9 Now, multiply by x2x^2: (x26x+9)x2=x46x3+9x2(x^2 - 6x + 9)x^2 = x^4 - 6x^3 + 9x^2 Now multiply by (x+1)(x + 1): (x46x3+9x2)(x+1)(x^4 - 6x^3 + 9x^2)(x + 1) Expanding: P(x)=x55x4+3x3+9x2P(x) = x^5 - 5x^4 + 3x^3 + 9x^2

Would you like a further breakdown of any of these steps?

Here are five related questions for practice:

  1. How do you handle multiplicities when forming polynomials from zeros?
  2. What happens to a polynomial's degree when one of the zeros has a multiplicity greater than 1?
  3. How do you expand polynomials with multiple terms like (x+4)3(x + 4)^3?
  4. What role does the leading coefficient play in the shape of the polynomial?
  5. How does the Fundamental Theorem of Algebra apply to the number of real zeros a polynomial can have?

Tip: Always double-check your factorizations and expansions to avoid mistakes in sign or arithmetic, especially when dealing with higher-degree polynomials.

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Math Problem Analysis

Mathematical Concepts

Polynomial Functions
Zeros and Multiplicity
Expansion of Polynomials

Formulas

(x - zero) represents the factor for each zero
Multiply the factors to form the polynomial

Theorems

Fundamental Theorem of Algebra

Suitable Grade Level

Grades 10-12