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The question asks at which point the graph of the function \( y = 2x + 1 \) intersects the x-axis. To find this point, we need to determine when \( y = 0 \) (i.e., when the function crosses the x-axis, or the "абсцисса").

We solve for \( x \) when \( y = 0 \):

\[
0 = 2x + 1
\]

\[
2x = -1
\]

\[
x = -\frac{1}{2}
\]

So, the point where the function intersects the x-axis is \( \left( -\frac{1}{2}, 0 \right) \), or \( (-0.5, 0) \).

Thus, the correct answer is:
**a. (-0.5; 0)**.

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Here are some related questions to explore further:
1. How do you determine where a function intersects the y-axis?
2. What is the slope of the line represented by \( y = 2x + 1 \)?
3. How do you graph a linear equation like \( y = 2x + 1 \)?
4. Can the slope of a linear function ever be zero?
5. What does the y-intercept of a linear function represent?

**Tip:** When solving for where a line crosses the x-axis, always set \( y = 0 \) and solve for \( x \).

График функции y = 2x + 1 пересекает ось абсцисс в точке:

Learn how to determine the point where the function y = 2x + 1 intersects the x-axis. This algebra problem involves setting y = 0 and solving for x. Suitable for students in Grades 6-8.

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