Math Problem Statement

Given the graph of the function, find the specified values. Copy the graph.

Solution

The graph shows a linear function, and from our previous analysis, we observed that it passes through the origin and has another clear point at (2, 3).

Steps to Find the Specified Values:

  1. Equation of the Line:

    • We previously calculated the slope as m=32m = \frac{3}{2} by using two points: (0, 0) and (2, 3).
    • The equation of the line, therefore, is f(x)=32xf(x) = \frac{3}{2}x.
  2. Finding Specific Values:

    • To find specific values like f(2)f(2) or f(5)f(5), we simply substitute these values into the equation f(x)=32xf(x) = \frac{3}{2}x.

Example Calculations:

  • f(2)f(2): f(2)=32×2=3f(2) = \frac{3}{2} \times 2 = 3 This matches our graph where the point (2, 3) lies on the line.

  • f(5)f(5): f(5)=32×5=7.5f(5) = \frac{3}{2} \times 5 = 7.5 This is a calculated value that would be located on the line if we extended the graph to x=5x = 5.

If there are specific points or values you would like me to calculate from this graph, please let me know!

Would you like further details or have any questions?

Related Questions to Explore:

  1. How do you determine the slope from any two points on a line?
  2. What is the relationship between the slope and the angle a line makes with the x-axis?
  3. How do you convert a linear equation in standard form to slope-intercept form?
  4. What happens to the graph if the slope is negative instead of positive?
  5. How do you graph a line given a point and the slope?

Tip: When interpreting graphs, always identify significant points like where the graph crosses the axes. This helps in determining the function's form and key values.

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Math Problem Analysis

Mathematical Concepts

Linear Functions
Graph Interpretation
Point-Gradient Form of a Line

Formulas

Point-Slope Form of a Line

Theorems

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Suitable Grade Level

Grades 7-9